Using the equations 2 CHe (1) + 15 O2 (g) → 12 CO2 (g) + 6 H20 (g)AH° = -6271 kJ/mol 2 H2 (g) + O2 (g) → 2 H¿O (g) AH° = -483.6 kJ/mol C (s) + O2 (g) → CO2 (g) AH° = -393.5 kJ/mol Determine the enthalpy for the reaction 6 C (s) + 3 H2 (g) → CóHe (1). kJ/mol

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Using the equations determine the enthalpy for the reaction

**Question 6 of 6**

**Using the equations:**

1. \(2 \, \text{C}_6\text{H}_6 \, (\text{l}) + 15 \, \text{O}_2 \, (\text{g}) \rightarrow 12 \, \text{CO}_2 \, (\text{g}) + 6 \, \text{H}_2\text{O} \, (\text{g}) \quad \Delta H^\circ = -6271 \, \text{kJ/mol}\)

2. \(2 \, \text{H}_2 \, (\text{g}) + \text{O}_2 \, (\text{g}) \rightarrow 2 \, \text{H}_2\text{O} \, (\text{g}) \quad \Delta H^\circ = -483.6 \, \text{kJ/mol}\)

3. \(\text{C} \, (\text{s}) + \text{O}_2 \, (\text{g}) \rightarrow \text{CO}_2 \, (\text{g}) \quad \Delta H^\circ = -393.5 \, \text{kJ/mol}\)

**Determine the enthalpy for the reaction:**

\(6 \, \text{C} \, (\text{s}) + 3 \, \text{H}_2 \, (\text{g}) \rightarrow \text{C}_6\text{H}_6 \, (\text{l}).\)

---

**Explanation:**

- The screen displays a calculator interface that includes a keypad for numerical input, featuring numbers 0-9, a decimal point, a +/- toggle, and buttons for clearing input or multiplying by ten. This is used for calculating the enthalpy change for the reaction. 

- The text above the calculator presents a thermochemistry problem that involves using given chemical equations and their respective standard enthalpy changes (\(\Delta H^\circ\)) to calculate the enthalpy change of formation for benzene (\(\text{C}_6\text{H}_6\)) from its elements in their standard states. This involves applying Hess's law.
Transcribed Image Text:**Question 6 of 6** **Using the equations:** 1. \(2 \, \text{C}_6\text{H}_6 \, (\text{l}) + 15 \, \text{O}_2 \, (\text{g}) \rightarrow 12 \, \text{CO}_2 \, (\text{g}) + 6 \, \text{H}_2\text{O} \, (\text{g}) \quad \Delta H^\circ = -6271 \, \text{kJ/mol}\) 2. \(2 \, \text{H}_2 \, (\text{g}) + \text{O}_2 \, (\text{g}) \rightarrow 2 \, \text{H}_2\text{O} \, (\text{g}) \quad \Delta H^\circ = -483.6 \, \text{kJ/mol}\) 3. \(\text{C} \, (\text{s}) + \text{O}_2 \, (\text{g}) \rightarrow \text{CO}_2 \, (\text{g}) \quad \Delta H^\circ = -393.5 \, \text{kJ/mol}\) **Determine the enthalpy for the reaction:** \(6 \, \text{C} \, (\text{s}) + 3 \, \text{H}_2 \, (\text{g}) \rightarrow \text{C}_6\text{H}_6 \, (\text{l}).\) --- **Explanation:** - The screen displays a calculator interface that includes a keypad for numerical input, featuring numbers 0-9, a decimal point, a +/- toggle, and buttons for clearing input or multiplying by ten. This is used for calculating the enthalpy change for the reaction. - The text above the calculator presents a thermochemistry problem that involves using given chemical equations and their respective standard enthalpy changes (\(\Delta H^\circ\)) to calculate the enthalpy change of formation for benzene (\(\text{C}_6\text{H}_6\)) from its elements in their standard states. This involves applying Hess's law.
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