C16H34 + 16.28 O2 +1.42 NH3 → 1.65 C4.4H7.301.2No.86 + 8.74 CO2 + 13.11 H2O For a particular bacterial strain, the molecular formula was determined to be C4.4H7.301.2No.86. These bacterial cells are grown under aerobic conditions with hexadecane (C16H34) as substrate. Assume that 60% of the hexadecane is used for producing cells (also called biomass) and the remaining 40% of the hexadecane is used for other cell functions. You have been put in charge of a small batch fermenter for growing the bacteria and aim to produce 10 kg of cells for inoculation of a pilot-scale reactor. a) Assuming this 60% conversion, what is the yield of cells from hexadecane in kg/kg?

Human Anatomy & Physiology (11th Edition)
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Chapter1: The Human Body: An Orientation
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**Transcription:**

**Equation:**

C₁₆H₃₄ + 16.28 O₂ + 1.42 NH₃ → 1.65 C₄.₄H₇.₃O₁.₂N₀.₈₆ + 8.74 CO₂ + 13.11 H₂O

For a particular bacterial strain, the molecular formula was determined to be C₄.₄H₇.₃O₁.₂N₀.₈₆. These bacterial cells are grown under aerobic conditions with hexadecane (C₁₆H₃₄) as substrate.

Assume that 60% of the hexadecane is used for producing cells (also called biomass) and the remaining 40% of the hexadecane is used for other cell functions. You have been put in charge of a small batch fermenter for growing the bacteria and aim to produce 10 kg of cells for inoculation of a pilot-scale reactor.

a) Assuming this 60% conversion, what is the yield of cells from hexadecane in kg/kg?

**Answer:** 0.401
Transcribed Image Text:**Transcription:** **Equation:** C₁₆H₃₄ + 16.28 O₂ + 1.42 NH₃ → 1.65 C₄.₄H₇.₃O₁.₂N₀.₈₆ + 8.74 CO₂ + 13.11 H₂O For a particular bacterial strain, the molecular formula was determined to be C₄.₄H₇.₃O₁.₂N₀.₈₆. These bacterial cells are grown under aerobic conditions with hexadecane (C₁₆H₃₄) as substrate. Assume that 60% of the hexadecane is used for producing cells (also called biomass) and the remaining 40% of the hexadecane is used for other cell functions. You have been put in charge of a small batch fermenter for growing the bacteria and aim to produce 10 kg of cells for inoculation of a pilot-scale reactor. a) Assuming this 60% conversion, what is the yield of cells from hexadecane in kg/kg? **Answer:** 0.401
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