C16H34 + 16.28 O2 +1.42 NH3 → 1.65 C4.4H7.301.2No.86 + 8.74 CO2 + 13.11 H20 For a particular bacterial strain, the molecular formula was determined to be C4.4H7.301.2No.86. These bacterial cells are grown under aerobic conditions with hexadecane (C16H34) as substrate. I Assume that 60% of the hexadecane is used for producing cells (also called biomass) and the remaining 40% of the hexadecane is used for other cell functions. You have been put in charge of a small batch fermenter for growing the bacteria and aim to produce 10 kg of cells for inoculation of a pilot-scale reactor. a) Assuming this 60% conversion, what is the yield of cells from hexadecane in kg/kg? b) What minimum amount of hexadecane substrate (in kg) must be contained in your culture medium? Remember that only 60% of the hexadecane is converted to cells. c) What must be the minimum concentration of hexadecane (in kg/m³) in the medium if the fermenter working volume is 4.3 cubic meters? Remember that only 60% of the hexadecane is converted to cells.
C16H34 + 16.28 O2 +1.42 NH3 → 1.65 C4.4H7.301.2No.86 + 8.74 CO2 + 13.11 H20 For a particular bacterial strain, the molecular formula was determined to be C4.4H7.301.2No.86. These bacterial cells are grown under aerobic conditions with hexadecane (C16H34) as substrate. I Assume that 60% of the hexadecane is used for producing cells (also called biomass) and the remaining 40% of the hexadecane is used for other cell functions. You have been put in charge of a small batch fermenter for growing the bacteria and aim to produce 10 kg of cells for inoculation of a pilot-scale reactor. a) Assuming this 60% conversion, what is the yield of cells from hexadecane in kg/kg? b) What minimum amount of hexadecane substrate (in kg) must be contained in your culture medium? Remember that only 60% of the hexadecane is converted to cells. c) What must be the minimum concentration of hexadecane (in kg/m³) in the medium if the fermenter working volume is 4.3 cubic meters? Remember that only 60% of the hexadecane is converted to cells.
Chapter10: Reconstitution Of Powdered Drugs
Section: Chapter Questions
Problem 6.4P
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Transcribed Image Text:C16H34 + 16.28 O2 +1.42 NH3 → 1.65 C4.4H7.301.2No.86 + 8.74 CO2 + 13.11 H20
For a particular bacterial strain, the molecular formula was determined to be C4.4H7.301.2No.86. These
bacterial cells are grown under aerobic conditions with hexadecane (C16H34) as substrate.
I
Assume that 60% of the hexadecane is used for producing cells (also called biomass) and the remaining
40% of the hexadecane is used for other cell functions. You have been put in charge of a small batch
fermenter for growing the bacteria and aim to produce 10 kg of cells for inoculation of a pilot-scale
reactor.
a) Assuming this 60% conversion, what is the yield of cells from hexadecane in kg/kg?
b) What minimum amount of hexadecane substrate (in kg) must be contained in your culture
medium? Remember that only 60% of the hexadecane is converted to cells.
c) What must be the minimum concentration of hexadecane (in kg/m³) in the medium if the
fermenter working volume is 4.3 cubic meters? Remember that only 60% of the hexadecane is
converted to cells.
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