c) Determine the earliest starting time, in days, for Activity H. d) Determine the latest starting time, in days, for Activity J.

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Given that, a
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B
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activity.
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Duration
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3
5
9
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6
4
2
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Preequisite
A
A
A
D
B
BIC
B, C
E, H
F
F
I
G, K,L
14
CD Finish
Required answer provided in above sten
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NOTE: We are allowed to do the first three sub-parts only.
1. Take the ES of the initial activity as 0.
2. Add duration to this ES to get EF.
3. This EF will become the ES for the succeeding activity/s.
4. If any activity has more than one preceding activity/s, then the higher EF will be taken as its ES.
5. This process will continue till the last activity.
6. For late times, start from the last activity and take its LF the same as its EF.
7. If there is more than one activity at the end, then the higher EF, among them, will be taken as the LF of all last activities.
8. Subtract duration from this LF to get the LS of the activity.
9. This LS will become the LF for the next previous activity/s.
10. If any activity has more than one successor, then the lower LS will be taken as its LF.
11. This process will continue till the first activity.
1. Take the ES of the initial activity as 0.
2. Add duration to this ES to get EF.
3. This EF will become the ES for the succeeding activity/s.
4. If any activity has more than one preceding activity/s, then the higher EF will be taken as its ES.
5. This process will continue till the last activity.
6. For late times, start from the last activity and take its LF the same as its EF.
7. If there is more than one activity at the end, then the higher EF, among them, will be taken as the LF of all last activities.
8. Subtract duration from this LF to get the LS of the activity.
9. This LS will become the LF for the next previous activity/s.
10. If any activity has more than one successor, then the lower LS will be taken as its LF.
11. This process will continue till the first activity.
Step by step
Solved in 4 steps with 2 images
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