Answered: PHSG298 1 rxn Volumes Needed Plasmid…

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Biochemistry

PHSG298 1 rxn Volumes Needed Plasmid 150 ng (30ng/ul) Water Total volume 30ul 30ul

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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The data in the table are used to create a calibration curve for the determination of RNA from ts absorbance at 260 nm. Use a spreadsheet and the least-squares method to determine the slope and y-intercept of the best straight line fit to the calibration curve. Do not subtract the blank reading when creating the calibration curve. m = b = RNA (µg) 0.00 10.36 20.72 31.08 41.44 Absorbance at 260 nm 0.268 0.497 0.795 1.131 1.373 Hig Using the slope and intercept of the calibration curve, determine the quantity of RNA in a sample that gives an absorbance of 0.699.
8L.Part I
Assume that the extinction coefficient for DNA at 260 nm is 20 g-1 x L x cm-1. What would be the DNA concentration of a solution if its 25x dilution has an absorbance at 260 nm of 0.6?
1 pt pt 9146 Bb 9146 Bb 1031 Class Etsy E Traps E Traps New Free Chat + ☆ 出口 keAssignment/takeCovalentActivity.do?locator-assignment-take [References] You do an enzyme kinetic experiment and calculate a Vmax of 118 μmol per minute. If each assay used 0.10 mL of an enzyme solution that had a concentration of 0.20 mg/mL, what would be the turnover number if the enzyme had a molecular weight of 128,000 g/mol? (Enter your answer to two significant figures.) turnover number = sec-1 D 1 pt Submit Answer Try Another Version 2 item attempts remaining estion stion 5 on 6 7 1pt 1 pt 1 pt 1pt 1pt 1pt 1 pt 1 pt D is the substrate concentration multiplied by the catalytic constant. KM is equivalent to the substrate concentration multiplied by the ratio of rate constants for the formation and dissociation of the enzyme-substrate complex. KM is equivalent to the substrate concentration. KM is equivalent to the substrate concentration divided by 2 A: KM is equivalent to the substrate concentration…
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Convert the words into past tense and passive voice.