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QUESTION 17 calculate the KM AND the total amount of enzyme present in these experiments. The following equations relate to this question. (Hint 1: some data is directly apparent without need to do calculations; Hint 2: Watch your exponents.) Kcat= Substrate concentration (mm) 1 2 4 6 100 1,000 The turnover number for an enzyme is known to be 5,000 min-1. From the following set of data, 250 334 376 500 500 Vmax [Et] Initial velocity (μmol/min) 167 G. 10 mM H. 250 uM 1. 2 mM J. 100 mM Part 1 Total Enzyme amount (choose from options A-E) Part 2 ( Enzyme KM: (choose from options G-J) A. Total enzyme = 10 umol B. Total enzyme = 0.1 umol OC. Total enzyme = 100 μmol D. Total enzyme = 1000 μmol E. Total enzyme = 10 μmol OF Vo = Vmax[S] KM + [S]

QUESTION 17 calculate the KM AND the total amount of enzyme present in these experiments. The following equations relate to this question. (Hint 1: some data is directly apparent without need to do calculations; Hint 2: Watch your exponents.) Kcat= Substrate concentration (mm) 1 2 4 6 100 1,000 The turnover number for an enzyme is known to be 5,000 min-1. From the following set of data, 250 334 376 500 500 Vmax [Et] Initial velocity (μmol/min) 167 G. 10 mM H. 250 uM 1. 2 mM J. 100 mM Part 1 Total Enzyme amount (choose from options A-E) Part 2 ( Enzyme KM: (choose from options G-J) A. Total enzyme = 10 umol B. Total enzyme = 0.1 umol OC. Total enzyme = 100 μmol D. Total enzyme = 1000 μmol E. Total enzyme = 10 μmol OF Vo = Vmax[S] KM + [S]

Biochemistry
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
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QUESTION 17 calculate the KM AND the total amount of enzyme present in these experiments. The following equations relate to this question. (Hint 1: some data is directly apparent without need to do calculations; Hint 2: Watch your exponents.) Kcat= Substrate concentration (mm) 1 2 4 6 100 1,000 The turnover number for an enzyme is known to be 5,000 min-1. From the following set of data, 250 334 376 500 500 Vmax [Et] Initial velocity (μmol/min) 167 G. 10 mM H. 250 uM 1. 2 mM J. 100 mM Part 1 Total Enzyme amount (choose from options A-E) Part 2 ( Enzyme KM: (choose from options G-J) A. Total enzyme = 10 umol B. Total enzyme = 0.1 umol OC. Total enzyme = 100 μmol D. Total enzyme = 1000 μmol E. Total enzyme = 10 μmol OF Vo = Vmax[S] KM + [S]
Transcribed Image Text:QUESTION 17 calculate the KM AND the total amount of enzyme present in these experiments. The following equations relate to this question. (Hint 1: some data is directly apparent without need to do calculations; Hint 2: Watch your exponents.) Kcat= Substrate concentration (mm) 1 2 4 6 100 1,000 The turnover number for an enzyme is known to be 5,000 min-1. From the following set of data, 250 334 376 500 500 Vmax [Et] Initial velocity (μmol/min) 167 G. 10 mM H. 250 uM 1. 2 mM J. 100 mM Part 1 Total Enzyme amount (choose from options A-E) Part 2 ( Enzyme KM: (choose from options G-J) A. Total enzyme = 10 umol B. Total enzyme = 0.1 umol OC. Total enzyme = 100 μmol D. Total enzyme = 1000 μmol E. Total enzyme = 10 μmol OF Vo = Vmax[S] KM + [S]
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