Based on the thermodynamic properties provided for methanol (below), select from the following list the equation(s) necessary tocalculate the amount of energy needed for 5.0 kg of methanol to go from -64°C to 88°C.PropertyValueUnitsMelting point-94°CBoiling point65°CAHfus3.18kJ/molAHvap37kJ/mol615)48.7 J/mol.°CCp (1)81.1J/mol.°C5 (8)43.8J/mol °CChoose one or more:A. q = n(43.8 J/mol °C)AT, where AT is negativeB. q=n(48.7 J/mol ·°C)AT, where AT is negativeC. q= n(81.1 J/mol -°C)AT, where A Tis negativeD. q = n(43.8 J/mol °C)AT, where A Tis positiveE. q=n(-3.18 kJ/mol)F. q- n(37 kJ/mol)G. q=n(-37 kJ/mol)H. q- n(3.18 kJ/mol)1.q=n(48.7 J/mol °C)AT, where AT is positiveJ.q=n(81.1 J/mol °C)AT, where A Tis positive

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Based on the thermodynamic properties provided for methanol (below), select from the following list the equation(s) necessary to calculate the amount of energy needed for 5.0 kg of methanol to go from -64°C to 88°C.

Based on the thermodynamic properties provided for methanol (below), select from the following list the equation(s) necessary to calculate the amount of energy needed for 5.0 kg of methanol to go from -64°C to 88°C.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Based on the thermodynamic properties provided for methanol (below), select from the following list the equation(s) necessary to
calculate the amount of energy needed for 5.0 kg of methanol to go from -64°C to 88°C.
Property
Value
Units
Melting point
-94
°C
Boiling point
65
°C
AHfus
3.18
kJ/mol
AHvap
37
kJ/mol
615)
48.7 J/mol.°C
Cp (1)
81.1
J/mol.°C
5 (8)
43.8
J/mol °C
Choose one or more:
A. q = n(43.8 J/mol °C)AT, where AT is negative
B. q=n(48.7 J/mol ·°C)AT, where AT is negative
C. q= n(81.1 J/mol -°C)AT, where A Tis negative
D. q = n(43.8 J/mol °C)AT, where A Tis positive
E. q=n(-3.18 kJ/mol)
F. q- n(37 kJ/mol)
G. q=n(-37 kJ/mol)
H. q- n(3.18 kJ/mol)
1.q=n(48.7 J/mol °C)AT, where AT is positive
J.q=n(81.1 J/mol °C)AT, where A Tis positive

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