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Based on the thermodynamic properties provided for methanol (below), select from the following list the equation(s) necessary to calculate the amount of energy needed for 5.0 kg of methanol to go from -64°C to 88°C.

Based on the thermodynamic properties provided for methanol (below), select from the following list the equation(s) necessary to calculate the amount of energy needed for 5.0 kg of methanol to go from -64°C to 88°C.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter6: Thermochemistry
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Based on the thermodynamic properties provided for methanol (below), select from the following list the equation(s) necessary to calculate the amount of energy needed for 5.0 kg of methanol to go from -64°C to 88°C. Property Value Units Melting point -94 °C Boiling point 65 °C AHfus 3.18 kJ/mol AHvap 37 kJ/mol 615) 48.7 J/mol.°C Cp (1) 81.1 J/mol.°C 5 (8) 43.8 J/mol °C Choose one or more: A. q = n(43.8 J/mol °C)AT, where AT is negative B. q=n(48.7 J/mol ·°C)AT, where AT is negative C. q= n(81.1 J/mol -°C)AT, where A Tis negative D. q = n(43.8 J/mol °C)AT, where A Tis positive E. q=n(-3.18 kJ/mol) F. q- n(37 kJ/mol) G. q=n(-37 kJ/mol) H. q- n(3.18 kJ/mol) 1.q=n(48.7 J/mol °C)AT, where AT is positive J.q=n(81.1 J/mol °C)AT, where A Tis positive
Transcribed Image Text:Based on the thermodynamic properties provided for methanol (below), select from the following list the equation(s) necessary to calculate the amount of energy needed for 5.0 kg of methanol to go from -64°C to 88°C. Property Value Units Melting point -94 °C Boiling point 65 °C AHfus 3.18 kJ/mol AHvap 37 kJ/mol 615) 48.7 J/mol.°C Cp (1) 81.1 J/mol.°C 5 (8) 43.8 J/mol °C Choose one or more: A. q = n(43.8 J/mol °C)AT, where AT is negative B. q=n(48.7 J/mol ·°C)AT, where AT is negative C. q= n(81.1 J/mol -°C)AT, where A Tis negative D. q = n(43.8 J/mol °C)AT, where A Tis positive E. q=n(-3.18 kJ/mol) F. q- n(37 kJ/mol) G. q=n(-37 kJ/mol) H. q- n(3.18 kJ/mol) 1.q=n(48.7 J/mol °C)AT, where AT is positive J.q=n(81.1 J/mol °C)AT, where A Tis positive
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