When one mole of HgO(s) decomposes to form one mole of Hg(1) and ½ mole of O2(g) the change in enthalpy for the reaction is +90.7 kJ. What quantity of heat is required to produce 1 mole of O2(g) by this reaction? O-181 kJ O +181 kJ O-90.7 kJ O +90.7 kJ
When one mole of HgO(s) decomposes to form one mole of Hg(1) and ½ mole of O2(g) the change in enthalpy for the reaction is +90.7 kJ. What quantity of heat is required to produce 1 mole of O2(g) by this reaction? O-181 kJ O +181 kJ O-90.7 kJ O +90.7 kJ
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
Transcribed Image Text:When one mole of HgO(s) decomposes to form one mole of Hg(1) and ½ mole of O2(g) the change in enthalpy for the reaction is +90.7 kJ. What quantity of heat is required
to produce 1 mole of O2(g) by this reaction?
-181 kJ
+181 kJ
-90.7 kJ
+90.7 kJ
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This question is answered by using the simple concept of calculation of heat change using the thermochemical equation and the stoichiometry which involves the relationship between moles and the heat.
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