A solid 30.2 cm block of KCIO, is heated in the laboratory and decomposes according to the following reaction. What is the change in enthalpy in kJ when all the solid KCIO, decomposes? The density of KCIO, is 2.34 g/cm 2 KCIO,(s) - 2 KCI(s) + 3 02(g) AH = -89.4 kJ STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) -25.8 -42.4 2 2.34 -11 30.2 -89.4 74.55 -51.6 32.00 122.55 6.022 x 10 g O2 mol KCIO, cm g KCIO, mol KCI g KCI mol O, kJ g/cm J
A solid 30.2 cm block of KCIO, is heated in the laboratory and decomposes according to the following reaction. What is the change in enthalpy in kJ when all the solid KCIO, decomposes? The density of KCIO, is 2.34 g/cm 2 KCIO,(s) - 2 KCI(s) + 3 02(g) AH = -89.4 kJ STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) -25.8 -42.4 2 2.34 -11 30.2 -89.4 74.55 -51.6 32.00 122.55 6.022 x 10 g O2 mol KCIO, cm g KCIO, mol KCI g KCI mol O, kJ g/cm J
Chemistry
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Chapter1: Chemical Foundations
Section: Chapter Questions
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![**Question 14 of 23**
A solid \(30.2 \, \text{cm}^3\) block of KClO\(_3\) is heated in the laboratory and decomposes according to the following reaction. What is the change in enthalpy in \(kJ\) when all the solid KClO\(_3\) decomposes? The density of KClO\(_3\) is \(2.34 \, \text{g/cm}^3\).
\[
2 \, \text{KClO}_3(s) \rightarrow 2 \, \text{KCl}(s) + 3 \, \text{O}_2(g) \quad \Delta H = -89.4 \, \text{kJ}
\]
---
**Interface Description**
- **Starting Amount Section**: Input area for beginning quantities.
- **Calculation Section**: Allows multiplication of different parameters.
- **Reset Button**: Clears current entries.
**Values Available for Calculation**
- \(-25.8\)
- \(-42.4\)
- \(3\)
- \(2.34\) (density of KClO\(_3\))
- \(-11\)
- \(1\)
- \(30.2\) (\(\text{cm}^3\) of KClO\(_3\))
**Units**
- mol \( \text{O}_2 \)
- g \( \text{O}_2 \)
- kJ
- mol KClO\(_3\)
- \(\text{g/cm}^3\)
- g KClO\(_3\)
- mol KCl
- g KCl
---
**Note**: Use the provided values and units to calculate the change in enthalpy due to the decomposition of KClO\(_3\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1f2e0728-2b17-46d6-b1f0-6681d1092eaa%2F9882268c-bfec-45c2-8bc1-ee363bab3746%2Fcofsy0p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question 14 of 23**
A solid \(30.2 \, \text{cm}^3\) block of KClO\(_3\) is heated in the laboratory and decomposes according to the following reaction. What is the change in enthalpy in \(kJ\) when all the solid KClO\(_3\) decomposes? The density of KClO\(_3\) is \(2.34 \, \text{g/cm}^3\).
\[
2 \, \text{KClO}_3(s) \rightarrow 2 \, \text{KCl}(s) + 3 \, \text{O}_2(g) \quad \Delta H = -89.4 \, \text{kJ}
\]
---
**Interface Description**
- **Starting Amount Section**: Input area for beginning quantities.
- **Calculation Section**: Allows multiplication of different parameters.
- **Reset Button**: Clears current entries.
**Values Available for Calculation**
- \(-25.8\)
- \(-42.4\)
- \(3\)
- \(2.34\) (density of KClO\(_3\))
- \(-11\)
- \(1\)
- \(30.2\) (\(\text{cm}^3\) of KClO\(_3\))
**Units**
- mol \( \text{O}_2 \)
- g \( \text{O}_2 \)
- kJ
- mol KClO\(_3\)
- \(\text{g/cm}^3\)
- g KClO\(_3\)
- mol KCl
- g KCl
---
**Note**: Use the provided values and units to calculate the change in enthalpy due to the decomposition of KClO\(_3\).
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