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4. Recall that when you combined the equations for Reactions (I) and (II) in the second Prelaboratory Question, you reversed the direction of Reaction (I). If a reaction is exothermic in one direction, reversing the direction (products-reactants) changes the sign, but not the magnitude, of 4H. Use your results from question 3 to determine values for AHI, AH2, and AH3, as identified below. Watch signs and be sure to include appropriate units. Space has been left to show your work. Notice that AH, is for the reverse of Reaction (I). Reaction Na (aq) + OH (aq) - NaOH(s) NaOH(s) + HC₂H₂O₂(aq) - →H₂O() + Na'(aq) + C₂H₂O₂ (aq) Na (aq) + OH(aq) + HC₂H₂O₂(aq) - H₂O() + Na (aq) + C₂H₂O₂ (aq) 5. Calculate the sum of AH, and AH₂. Show your work. ΔΗ, = AH₂ ΔΗ, = AH

4. Recall that when you combined the equations for Reactions (I) and (II) in the second Prelaboratory Question, you reversed the direction of Reaction (I). If a reaction is exothermic in one direction, reversing the direction (products-reactants) changes the sign, but not the magnitude, of 4H. Use your results from question 3 to determine values for AHI, AH2, and AH3, as identified below. Watch signs and be sure to include appropriate units. Space has been left to show your work. Notice that AH, is for the reverse of Reaction (I). Reaction Na (aq) + OH (aq) - NaOH(s) NaOH(s) + HC₂H₂O₂(aq) - →H₂O() + Na'(aq) + C₂H₂O₂ (aq) Na (aq) + OH(aq) + HC₂H₂O₂(aq) - H₂O() + Na (aq) + C₂H₂O₂ (aq) 5. Calculate the sum of AH, and AH₂. Show your work. ΔΗ, = AH₂ ΔΗ, = AH

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Pre Lab O 2. Recopy equations (18-1) and (18-2) from the introduction, but reverse equation (18-1) so that solid sodium hydroxide appears on the products side of the arrow and the dissolved ions appear as reactants. Now add the two equations, just as you would in algebra when solving two equations in two unknowns. Na+ (aq) + OH-caq) → Nagh(s) NaOH(s) OH(aq) + + HC ₂ H 30₂(aq) → H₂0 (₁) + Na + (aq) + C ₂ H 30₂¯ (aq) 2 2 MC ₂ H 3 O ₂ (aq) → M₂ Oc₁ + C ₂ H 3 O ₂¯ (aq)
Transcribed Image Text:Pre Lab O 2. Recopy equations (18-1) and (18-2) from the introduction, but reverse equation (18-1) so that solid sodium hydroxide appears on the products side of the arrow and the dissolved ions appear as reactants. Now add the two equations, just as you would in algebra when solving two equations in two unknowns. Na+ (aq) + OH-caq) → Nagh(s) NaOH(s) OH(aq) + + HC ₂ H 30₂(aq) → H₂0 (₁) + Na + (aq) + C ₂ H 30₂¯ (aq) 2 2 MC ₂ H 3 O ₂ (aq) → M₂ Oc₁ + C ₂ H 3 O ₂¯ (aq)
4. Recall that when you combined the equations for Reactions (I) and (II) in the second Prelaboratory Question, you reversed the direction of Reaction (I). If a reaction is exothermic in one direction, reversing the direction (products reactants) changes the sign, but not the magnitude, of 4H. Use your results from question 3 to determine values for AHI, AH2, and AH3, as identified below. Watch signs and be sure to include appropriate units. Space has been left to show your work. Notice that AH, is for the reverse of Reaction (I). Reaction Na (aq) + OH (aq) → NaOH(s) NaOH(s) + HC₂H3O₂(aq) → H₂O() + Na (aq) + C₂H3O₂ (aq) Na (aq) + OH (aq) + HC₂H3O₂(aq) → H₂O() + Na (aq) + C₂H3O₂ (aq) 5. Calculate the sum of AH₁ and AH2. Show your work. AH for Reaction 1 AH for Reaction 2 AH for Reaction 3 3. The quantities and concentrations of the two solutions used in Reaction III were sen so that 0.0500 moles of sodium hydroxide would be present. Use this information and the numbers of moles of NaOH you calculated in question 2 to convert your values of q from question 1 to AH values, in kJ/mol. -2481.086 J x 0.0500 moles -4699.92J x 0.0500 -2635-92J X IKJ 1000 3 moles 0.0500 IKJ 10003 IKJ 10000 AH, = moles ΔΗ, = ΔΗ; = こ ΔΗ こ -49.6 = -१५.० -52.7 KJ mol KJ mol K3 mol
Transcribed Image Text:4. Recall that when you combined the equations for Reactions (I) and (II) in the second Prelaboratory Question, you reversed the direction of Reaction (I). If a reaction is exothermic in one direction, reversing the direction (products reactants) changes the sign, but not the magnitude, of 4H. Use your results from question 3 to determine values for AHI, AH2, and AH3, as identified below. Watch signs and be sure to include appropriate units. Space has been left to show your work. Notice that AH, is for the reverse of Reaction (I). Reaction Na (aq) + OH (aq) → NaOH(s) NaOH(s) + HC₂H3O₂(aq) → H₂O() + Na (aq) + C₂H3O₂ (aq) Na (aq) + OH (aq) + HC₂H3O₂(aq) → H₂O() + Na (aq) + C₂H3O₂ (aq) 5. Calculate the sum of AH₁ and AH2. Show your work. AH for Reaction 1 AH for Reaction 2 AH for Reaction 3 3. The quantities and concentrations of the two solutions used in Reaction III were sen so that 0.0500 moles of sodium hydroxide would be present. Use this information and the numbers of moles of NaOH you calculated in question 2 to convert your values of q from question 1 to AH values, in kJ/mol. -2481.086 J x 0.0500 moles -4699.92J x 0.0500 -2635-92J X IKJ 1000 3 moles 0.0500 IKJ 10003 IKJ 10000 AH, = moles ΔΗ, = ΔΗ; = こ ΔΗ こ -49.6 = -१५.० -52.7 KJ mol KJ mol K3 mol
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