What is the change in enthalpy in kilojoules when 2.30 mol of Mg is completely reacted according to the following reaction Mg(s) + O2(g) → MgO(s) AH = -1204 kJ

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**Question 15 of 15**

**Topic: Thermodynamics - Enthalpy Change in Reactions**

**Problem Statement:**
Calculate the change in enthalpy (in kilojoules) when 2.30 moles of magnesium (Mg) react completely according to the following reaction:

\[ 2 \text{Mg(s)} + \text{O}_2\text{(g)} \rightarrow 2 \text{MgO(s)} \]

The enthalpy change (\( \Delta H \)) for the reaction is given as \(-1204 \text{ kJ}\).

**Calculation Steps:**

1. **Starting Amount:** Input the amount of Mg reacting (2.30 mol) into the left box labeled "STARTING AMOUNT."

2. **Use the Reaction Stoichiometry:**
   - The balanced chemical equation shows that 2 moles of Mg produce an enthalpy change of \(-1204 \text{ kJ}\).

3. **Calculate the Enthalpy Change for 2.30 mol of Mg:**

   - Input the appropriate values into the provided equation format: 

      \[
      \text{Enthalpy Change} = \left( \frac{\text{Starting Amount (moles)}}{\text{Stoichiometric Coefficient (moles)}} \right) \times \Delta H_{\text{reaction}}
      \]

   - Here:
     - Starting Amount = 2.30 mol
     - Stoichiometric Coefficient = 2 mol
     - \(\Delta H_{\text{reaction}} = -1204 \text{ kJ}\)

4. **Compute the Enthalpy Change:**
   - Use the provided calculation tools to find the final enthalpy change.

**Interface:**
- A calculation field and result display panel are included for user input and solving.
- Below the calculation interface are options to adjust factors and reset the input.

**Additional Resources:**
- Click on the provided link for more learning materials about enthalpy and thermodynamics.

This problem helps deepen understanding of reaction enthalpy changes, particularly in calculating real-world chemical energy changes from stoichiometric ratios.
Transcribed Image Text:**Question 15 of 15** **Topic: Thermodynamics - Enthalpy Change in Reactions** **Problem Statement:** Calculate the change in enthalpy (in kilojoules) when 2.30 moles of magnesium (Mg) react completely according to the following reaction: \[ 2 \text{Mg(s)} + \text{O}_2\text{(g)} \rightarrow 2 \text{MgO(s)} \] The enthalpy change (\( \Delta H \)) for the reaction is given as \(-1204 \text{ kJ}\). **Calculation Steps:** 1. **Starting Amount:** Input the amount of Mg reacting (2.30 mol) into the left box labeled "STARTING AMOUNT." 2. **Use the Reaction Stoichiometry:** - The balanced chemical equation shows that 2 moles of Mg produce an enthalpy change of \(-1204 \text{ kJ}\). 3. **Calculate the Enthalpy Change for 2.30 mol of Mg:** - Input the appropriate values into the provided equation format: \[ \text{Enthalpy Change} = \left( \frac{\text{Starting Amount (moles)}}{\text{Stoichiometric Coefficient (moles)}} \right) \times \Delta H_{\text{reaction}} \] - Here: - Starting Amount = 2.30 mol - Stoichiometric Coefficient = 2 mol - \(\Delta H_{\text{reaction}} = -1204 \text{ kJ}\) 4. **Compute the Enthalpy Change:** - Use the provided calculation tools to find the final enthalpy change. **Interface:** - A calculation field and result display panel are included for user input and solving. - Below the calculation interface are options to adjust factors and reset the input. **Additional Resources:** - Click on the provided link for more learning materials about enthalpy and thermodynamics. This problem helps deepen understanding of reaction enthalpy changes, particularly in calculating real-world chemical energy changes from stoichiometric ratios.
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