Based on the kinetic constants below, which enzyme will most efficiently catalyze conversion of the substrate into product? A) Vmax = 10 uM s-1, KM = 10 µM B) Vmax = 10 uM s-1, KM = 0.01 µM C) Vmax = 1000 uM s-1, KM = 500 µM D) Vmax = 1 uM s-1, KM = 1 µM E) Vmax = 200 uM s-1, KM = 10 µM

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