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Assignment on determining whether specified MOI is consistent with observed data In this assignment, I would like you to compute the chi-square goodness of fit test for an observed data set, using two different MOIS. A critically important point in our work is that MOI just means the proportions that correspond to the different phenotypes. For this exercise, the two MOIS are Autosomal Dominant (AD) and Sex Linked Recessive (SLR). The data in the table below is the counts of F2 offspring from an F₁ cross. We use the following notation for the alleles at the gene of interest: Notation: D = disease allele at gene d = wild-type allele at gene Let's provide some information about each MOI. AD: Each of the Fi parents is heterozygous for the D allele. SLR: The observed F₂ data are the offspring from an F₁ cross where the father is affected (disease) and the mother is an unaffected carrier (wild-type, or WT). That is, the mother's genotype has one disease allele and one WT allele in it. In Table 1, I provide the observed data counts (in dark blue). Notice that I stratify by gender. Table 1. 0 E O-E (O-E)² Phenotype Disease, Male 304 Disease, Female 267 WT, Male 285 WT, Female Total 301 1157 DF p-value (O-E)²/E

Assignment on determining whether specified MOI is consistent with observed data In this assignment, I would like you to compute the chi-square goodness of fit test for an observed data set, using two different MOIS. A critically important point in our work is that MOI just means the proportions that correspond to the different phenotypes. For this exercise, the two MOIS are Autosomal Dominant (AD) and Sex Linked Recessive (SLR). The data in the table below is the counts of F2 offspring from an F₁ cross. We use the following notation for the alleles at the gene of interest: Notation: D = disease allele at gene d = wild-type allele at gene Let's provide some information about each MOI. AD: Each of the Fi parents is heterozygous for the D allele. SLR: The observed F₂ data are the offspring from an F₁ cross where the father is affected (disease) and the mother is an unaffected carrier (wild-type, or WT). That is, the mother's genotype has one disease allele and one WT allele in it. In Table 1, I provide the observed data counts (in dark blue). Notice that I stratify by gender. Table 1. 0 E O-E (O-E)² Phenotype Disease, Male 304 Disease, Female 267 WT, Male 285 WT, Female Total 301 1157 DF p-value (O-E)²/E

Human Anatomy & Physiology (11th Edition)
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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Assignment on determining whether specified MOI is consistent with observed data In this assignment, I would like you to compute the chi-square goodness of fit test for an observed data set, using two different MOIS. A critically important point in our work is that MOI just means the proportions that correspond to the different phenotypes. For this exercise, the two MOIS are Autosomal Dominant (AD) and Sex Linked Recessive (SLR). The data in the table below is the counts of F2 offspring from an F1 cross. We use the following notation for the alleles at the gene of interest: Notation: D = disease allele at gene d = wild-type allele at gene Let's provide some information about each MOI. AD: Each of the Fi parents is heterozygous for the D allele. SLR: The observed F2 data are the offspring from an Fi cross where the father is affected (disease) and the mother is an unaffected carrier (wild-type, or WT). That is, the mother's genotype has one disease allele and one WT allele in it. In Table 1, I provide the observed data counts (in dark blue). Notice that I stratify by gender. Table 1. (0-E)² (O-E)/E Phenotype Disease, Male Disease, Female WT, Male E O-E 304 267 285 WT, Female 301 Total 1157 DF p-value 1| Page
Transcribed Image Text:Assignment on determining whether specified MOI is consistent with observed data In this assignment, I would like you to compute the chi-square goodness of fit test for an observed data set, using two different MOIS. A critically important point in our work is that MOI just means the proportions that correspond to the different phenotypes. For this exercise, the two MOIS are Autosomal Dominant (AD) and Sex Linked Recessive (SLR). The data in the table below is the counts of F2 offspring from an F1 cross. We use the following notation for the alleles at the gene of interest: Notation: D = disease allele at gene d = wild-type allele at gene Let's provide some information about each MOI. AD: Each of the Fi parents is heterozygous for the D allele. SLR: The observed F2 data are the offspring from an Fi cross where the father is affected (disease) and the mother is an unaffected carrier (wild-type, or WT). That is, the mother's genotype has one disease allele and one WT allele in it. In Table 1, I provide the observed data counts (in dark blue). Notice that I stratify by gender. Table 1. (0-E)² (O-E)/E Phenotype Disease, Male Disease, Female WT, Male E O-E 304 267 285 WT, Female 301 Total 1157 DF p-value 1| Page
In Table 2, provide expected proportions for two different MOIS: AD and SLR. The values in this table are computed using information from the Punnett Square and the specified MOI. Once the proportions are determined, we can fill in the values in Table 3, E(xpected) column. Table 2. AD proportions SLR proportions Phenotype Disease, Male Disease, Female WT, Male WT, Female Your assignment is to fill in Table 1 twice (make two copies of Table 1), once using the AD proportions in Table 2 to compute the E(xpected) column, and once using the SLR proportions in Table 2 to compute the E(xpected) column. Then, follow through, decide whether either/both/neither of the specified MOIS are consistent with the observed data, and report your results. I'll get you started with the AD MOI (Table 3): Table 3. (O-E)? (0-E)'/E Phenotype Disease, Male Disease, Female WT, Male E О-Е 304 =1157 x 0.375 (433.875) 285 267 WT, Female 301 =1157 x 0.125 (144.625) Total 1157 DF p-value You must fill in the rest of the cells, compute the Chi-Square statistic, determine the degrees of freedom (DF), compute the p-value, and determine whether you reject or do not reject the null hypothesis that you specified the correct MOI. Remember, you are doing this work for two MOIS, and remember to show all work. 2I Page
Transcribed Image Text:In Table 2, provide expected proportions for two different MOIS: AD and SLR. The values in this table are computed using information from the Punnett Square and the specified MOI. Once the proportions are determined, we can fill in the values in Table 3, E(xpected) column. Table 2. AD proportions SLR proportions Phenotype Disease, Male Disease, Female WT, Male WT, Female Your assignment is to fill in Table 1 twice (make two copies of Table 1), once using the AD proportions in Table 2 to compute the E(xpected) column, and once using the SLR proportions in Table 2 to compute the E(xpected) column. Then, follow through, decide whether either/both/neither of the specified MOIS are consistent with the observed data, and report your results. I'll get you started with the AD MOI (Table 3): Table 3. (O-E)? (0-E)'/E Phenotype Disease, Male Disease, Female WT, Male E О-Е 304 =1157 x 0.375 (433.875) 285 267 WT, Female 301 =1157 x 0.125 (144.625) Total 1157 DF p-value You must fill in the rest of the cells, compute the Chi-Square statistic, determine the degrees of freedom (DF), compute the p-value, and determine whether you reject or do not reject the null hypothesis that you specified the correct MOI. Remember, you are doing this work for two MOIS, and remember to show all work. 2I Page
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