A- What are advantages of fractional pitched armature windings?B- Derive an expression for the distribution factor (Kd) ?C- A heating load of 700 kW and a motor of 707 kW at 0.707 power factor are suppliedBy two alternators running in parallel .One of the alternators supplies 900 kW at0.9 power factor lagging. Find the load and power factor of the second alternator?

Step 1: Step 2: Step 3: Step 4:

Answered: A- What are advantages of fractional…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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4. A 2 MVA, 2.3kV, three-phase Wye connected alternator operates at rated kVA at a power factor of 80 %. The dc armature winding resistance between terminals is 0.08-ohm. The field takes 70-A at 125-V from the exciter equipment. Friction and windage loss is 20-kW, iron loss 36-kW and stray power loss are 2.0-kW. Calculate the efficiency of the alternator. Assume the effective armature winding resistance is 120% of the dc resistance.
A three-phase, 4-pole, 1,500 rpm alternating having a double layer-windings with 18 turns per coil. The slots per pole per phase are 10 and the coil span is 22 slots. The spread phase is 60 degrees and the flux per pole is 0.0625 Weber. If the armature windings are wye connected. a) Determine the generated voltage per phase and the line to line voltages. b) If the alternator is delivering a three - phase load of 1,200KW at 0.8 lagging power factor what is the line current of the alternator
The terminal voltage of a 150 kW series generator is 600 V at rated load. The armature resistance is 0.06 ohms and the series field resistance is 0.04 ohms. Find generated emf.
(12) An alternator which is operating in parallel with other alternators at rated terminal voltage has an armature resistance of 0.015 pu and synchronous reactance of 0.35 pu. It delivers a power output in kW equal to 0.8 of its rated kVA and the voltage regulation is equal to 15%. The power factor at which the machine is operating approximately equal to .........
A single phase, 2000 V alternator has armature resistance and reactance of 0.8 ohms and 4.94 ohms respectively. The voltage regulation of the alternator at 100 A load at 0.8 leading power factor is ??
3. A three-phase 60 Hz Wye connected, 2,000-kVA, 2,300-V alternator give a short circuit-test current of 600-A for a certain field excitation. With the same excitation, the open circuit-test voltage was 900-V. The resistance between a pair of terminal was 0.12-ohm. Find the full load regulation at a) unity power factor and b) 0.8 power factor.
b) Explain the conditions of parallel connection of alternators and how these conditions are fulfilled.
Determine the power angle characteristic for the system shown in figure. The generator is operating at a terminal voltage of 1.05p.u. and the infinite bus is at 1.p.u. voltage. The generator is supplying 0.7p.u power to the infinite bus. Draw the power angle curve in graph sheet.
H4
Full solutions for the question with explanation
Discussion:- 1. What do you understand by "armature- reaction"? Discuss the effect of armature reaction in an alternator when it is loaded with resistive, inductive and capacitive loads. 2. Give the value of voltage regulation for different power factors at full load current and interpret their values.
In a Three-phase alternator, a given field current produces an armature current of 250 A on short-circuit and a generated e.m.f. of 1500 V on open-circuit. Calculate the terminal p.d. when a load of 250 A at 6.6 kV and 0.8 p.f. lagging is switched off. Calculate also the regulation of the alternator at the given load. Subject: Electrical engineering

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