A standard solution of containing 6.3 x 10-8 M iodoacetone and 2.0 x 10-7 M p-dichlorobenzene(internal standard) gave peak areas of 395 and 787, respectively in a gas chromatogram. A 3.00-mL unknown solution of iodoacetone was treated with 0.100 mL of 1.6 x 10-5 Mp-dichlorobenzeneand the mixture was diluted to 10.00 mL Gas chromatography gave peak areas of 633 and 520 foriodoacetone and p-dichlorobenzene, respectively. Find the concentration of iodoacetone in the 3.00mL of original unknown.

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Answered: A standard solution of containing 6.3 x…

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter33: High-performance Liquid Chromatography

Section: Chapter Questions

Problem 33.2QAP

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A standard solution of containing 6.3 x 10-8 M iodoacetone and 2.0 x 10-7 M p-dichlorobenzene (internal standard) gave peak areas of 395 and 787, respectively in a gas chromatogram. A 3.00-mL unknown solution of iodoacetone was treated with 0.100 mL of 1.6 x 10-5 M p-dichlorobenzene and the mixture was diluted to 10.00 mL Gas chromatography gave peak areas of 633 and 520 for iodoacetone and p-dichlorobenzene, respectively. Find the concentration of iodoacetone in the 3.00 mL of original unknown.
A standard solution containing 6.3 x 10-8 M iodoacetone and 2.0 x 10-7 M p-dichlorobenzene (an internal standard) gave peak areas of 395 and 787, respectively, in a gas chromatogram. A 3 mL unknown solution of iodoacetone was treated with 0.100 mL of 1.6 x 10-5 M p-dichlorobenzene and the mixture was diluted to 10 mL. Gas chromatography gave peak areas of 633 and 520 for iodoacetone and p-dichlorobenzene respectively. Find the concentration of the iodoacetone in the 3 mL of original unknown.
Internal standard. A mixture containing 12.8 mM analyte (X) and 44.4 mM standard (S) gave chromatographic peak areas of 306 for X and 511 for S. A second solution containing an unknown quantity of X plus 55.5 mM S had peak areas of 251 for X and 563 for S. Find [X] in the second solution.
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Next, 2.00 mL of 9.63 mM S was added to 10.00 mL of a solution of unknown concentration of X, and the mixture was diluted to 25.0mL. Chromatographic analysis of this solution produced peak areas of 4822 for X and 4099 for S. What was the concentration of 5 (in mM) of the 25.0mL solution?
2. Thin layer chromatography was performed to find the most effective mobile phase needed to separate a mixture containing three compounds (using silica gel as the stationary phase). TLC analyses were performed using five different mobile phases: (A) pure petroleum ether; (B) 25:75 ethyl acetate:petroleum ether; (c) 50:50 ethyl acetate:petroleum ether (D) 75:25 ethyl acetate:petroleum ether; and (E) pure ethyl acetate. Using the TLC results provided, indicate whether an effective separation was achieved for each of the five mobile phases. Be sure to provide a brief explanation for your answer and identify which mobile phase(s) could be used to offer an effective separation of this mixture using column chromatography. A D E
In a chromatographic analysis, a solution containing 0.0837M toluene and 0.0666M xylene resulted in peak areas of Atoluene= 423 and Axylene= 347. To analyze an unknown sample, 10.0mL of 0.146M xylene was added to 10.0mL of an unknown toluene-containing solution, and the mixture was diluted to 25.0mL. This mixture gave a chromatogram with peak areas of Atoluene= 553 and Axylene= 582. What was the concentration of toluene in the unknown solution?
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1 24) The method of internal standard was used to analyze and measure the concentration of chemical X by GC A known mixture of compounds X and Y (internal standard) gave the following chromatographic results: Compound X Y Concentration (M) 6.3 x 10-8 2.0 x 10-7 a) 2.0 x 10-6 M b) 8.4 x 10-7 M c) 6.6 x 10-7 M d) 4.1 x 10-7 M e) 2.9 x 10-7 M Peak Area 395 787 Then, an unknown was analyzed as follows. 3.0 mL of unknown X was treated with 0.100 mL of 1.6 x 10-5 M Y and the mixture diluted to 10.0 mL final volume. Peak areas were 633 (for X) and 520 (for Y). What is the concentration of X in the unknown. (The original 3.00 sample?)
2. Different marker inks were analyzed using a simple paper chromatographyexperiment. Two marker inks were dissolved separately in a solvent and spottedin the chromatogram. The mobile phase used was 1% NaCl and three inkstandards (A-copper-phthalocyanine blue, B-diarylide yellow,C- lithol rubine red)were spotted beside the two sample markers. After the chromatography, thechromatogram showed a separation of colors in the two inks (D and E).a. Calculate the retention factor for each spot from lanes A to E .b. Which ink standard was the most polar? least polar?c. What is the composition of ink D ?
Internal standard. A solution containing 3.47 mM X (analyte) and 1.72 mM S (standard) gave peak areas of 3 473 and 10 222, respectively, in a chromatographic analysis. Then 1.00 mL of 8.47 mM S was added to 5.00 mL of unknown X, and the mixed solution was diluted to 10.0 mL. This solution gave peak areas of 5 428 and 4 431 for X and S, respectively. (a) Find the response factor for X relative to S in Equation 5-9. (b) Find [S] (mM) in the 10.0 mL of mixed solution. (c) Find [X] (mM) in the 10.0 mL of mixed solution.(d) Find [X] in the original unknown.
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