A solution containing 3.51 mM X (analyte) and 1.67 mM S (internal standard) gave peak areas of 3505 and 10437, respectively, in a chromatographic analysis. Then 1.00 mL of 8.47 mM S was added to 5.00 mL of unknown X, and the mixture was diluted to 10.0 mL. This solution gave peak areas of 5428 and 4431 for X and S, respectively. Answer the following questions and enter your results with numerical values only. Calculate the response factor for the analyte. (keep four significant figures) Find the concentration (mM) of X in the 16.0 mL of mixed solution. Find the concentration (mM) of X in the original unknown.

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A solution containing 3.51 mM X (analyte) and 1.67 mM S (internal standard) gave
peak areas of 3505 and 10437, respectively, in a chromatographic analysis. Then
1.00 mL of 8.47 mM S was added to 5.00 mL of unknown X, and the mixture was
diluted to 10.0 mL. This solution gave peak areas of 5428 and 4431 for X and S,
respectively. Answer the following questions and enter your results with
numerical values only.
Calculate the response factor for the analyte. (keep four significant figures)
Find the concentration (mM) of X in the 1Ó.0 mL of mixed solution.
Find the concentration (mM) of X in the original unknown.
Transcribed Image Text:A solution containing 3.51 mM X (analyte) and 1.67 mM S (internal standard) gave peak areas of 3505 and 10437, respectively, in a chromatographic analysis. Then 1.00 mL of 8.47 mM S was added to 5.00 mL of unknown X, and the mixture was diluted to 10.0 mL. This solution gave peak areas of 5428 and 4431 for X and S, respectively. Answer the following questions and enter your results with numerical values only. Calculate the response factor for the analyte. (keep four significant figures) Find the concentration (mM) of X in the 1Ó.0 mL of mixed solution. Find the concentration (mM) of X in the original unknown.
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