A spherical cell with the diameter of 10uMhas a protein concentration of 20 mg/ml. Determine the number of proteinmolecules within the cell if the molecular weight of an average protein is 50,000 daltons (g/mol). Recall that Avogadro'snumber is NA6.0221367×1023 molecules/mol.=

Detailed explanation:Total mass of protein in the cell = volume * density = ((4/3) *π * r3) * 20…

Answered: A spherical cell with the diameter of…

Curren'S Math For Meds: Dosages & Sol

11th Edition

ISBN:9781305143531

Author:CURREN

Publisher:CURREN

Chapter13: Dimensional Analysis/units Conversion

Section: Chapter Questions

Problem 1.3P

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2. 0.1 mL of a protein solution of concentration of 7 mg/mL was diluted to a total volume of 4.0 mL with water (i.e. 0.1 mL of the solution was added to 3.9 mL of water). 3 mL of this solution was then mixed with 27 mL of water. What is the concentration of the diluted protein solution? Space to show your workings:
Protein concentration can readily be determined using the Beer-Lambert law: A = e l c where A = absorbance e = molar absorption coefficient (M-1cm-1) l = light path length (cm) c = concentration (M) If the molar absorption coefficient at 280 nm for yeast ADH is 48860 M-1cm-1 and a 10 mL solution of the protein has an absorbance at 280 nm of 0.4 (as measured by a spectrometer with pathlength 1 cm), then what is the concentration of the protein solution (in μM)? i.e. concentration = ______ μM If the molecular weight of the protein is 36849, what is its concentration in mg/mL? i.e. concentration = _______ mg/mL For each part of the question, show your calculations to arrive at your answers.
Please answer the question below and show all your work. You are given a pure protein sample to characterize and provided the following information: Its molar extinction coefficient, ε280, is 0.25 liters micromole^-1 cm^-1 Using a 0.5 cm pathlength cell, you measure the absorbance at 280 nm of a 20- fold dilution of your pure protein in solution (by this, we mean that 50 ul of the protein sample was diluted to a final volume of 1 ml) and find A280 = 0.40. What is the original concentration of the protein before dilution?
Polymer beads (resin) made of DEAE (diethylaminoethyl) cellulose are packed in an ion exchange column. The total mass of beads in the column is 8.47 kg. On average, each bead weighs 0.0023 g and has an average of 18.4 * 10° positively charged amine groups that can adsorba negatively charged protein that passes through the column. A solution containing 2.07 mg/L of a protein is maintained at pH 6.3 and is passed through the ion exchange column at 0.215 L/min. The protein has a molecular weight of 154,000. The pk, of the amino groups on DEAE cellulose is 7.1, and the pl of the protein is 5.6. 2. A. How long can the column be operated before reaching 80% capacity (i.e., 80% of the amino groups on DEAE are bound to the protein through an ionic bond)? You may assume that one protein attaches to one + charge on the beads (although it's possible that proteins attach to more than one + charge). B. After reaching 80% capacity, explain what you would do to release the protein attached to the…
A large chaperone protein complex GroEL is approximately 16 nm in diameter. When it is dissolved in water at 300 K, estimate the average time it will take for GroEL to diffuse a distance of 500 nm (0.5 micron). The viscosity of water is 10-3 Pa*s.
6-73 In each case, tell which side (if either) rises and why. The solvent is water. A A Osmotic membrane (a) 1% glucose (b) 0.1 M glucose (c) 1 M NaCl (d) 1 M NaCl (e) 3% NaCl (f) 1 M NaBr (B) B 5% glucose 0.5 M glucose 1 M glucose 1 M K₂SO4 3% KC1 1 M KC1
The A280 of a protein sample loaded onto a gel was determined to be 0.767 (1.00 cm path length, after subtracting the blank). The total volume of this sample was 428 µL. 19.0 µL of this protein sample was mixed with 19.0 µL of 2X laemalli sample buffer and then 12.0 µL of the entire sample was loaded into the gel and electrophoresed. Calculate the amount of protein that was loaded into the gel (in µg).
Give only typing answer with explanation and conclusion You want to make 94 µL of the diluted Cell-Free extract for estimation of total protein. To do this, how much water will you add to the correct volume of the undiluted cell-free extract? Note: Cell-free extracts will need to be diluted 1:25 in water.
Using the equation for the best-fit straight line through your data, the average absorbance of your unknown samples U1 and U2, and any dilution factors (DON’T LEAVE OUT THE DILUTION FACTOR), calculate the concentration of protein in the original unknown protein sample. y = 1.6849x + 0.0414R² = 0.9904
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A spherical cell with the diameter of 10uMhas a protein concentration of 20 mg/ml. Determine the number of protein molecules within the cell if the molecular weight of an average protein is 50,000 daltons (g/mol). Recall that Avogadro's number is NA 6.0221367×1023 molecules/mol. =