A simply supported beam AB of span L = 24 m is subjected to 2 wheel loads acting at a distance d = 5m apart as shown in figure below. Each wheel transmits a load P = 3 kN and may Occupy %3D %3D %3D any position along the beam. If beam is an I- section having section modulus; S = 16.2 cm3,
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- A bridge girder AB on a simple span of length L = 30 m supports a distributed load of maximum intensity q at mid-span and minimum intensity q/2 at supports A and B that indudes the weight of the girder (see figure). 450 mm 32 mm B 30 m 16 mm- 1800 mm 32 mm 450 mm The girder is constructed of three plates welded to form the cross section shown. Determine the maximum permissible load q (in kN/m) based upon the following. (a) solely based on an allowable bending stress aallow = 110 MPa kN/m (b) solely based on an allowable shear stress tallow = 50 MPa kN/m (c) accounting for both an allowable bending stress ollow and an allowable shear stress Tallow kN/mAW250 x 32.7 structural steel [E = 200 GPa] wideflange shape is loaded and supported as shown. A uniformly distributed load of w= 13 kN/m is applied to the beam, causing the roller support at B to settle downward (i.e., displace downward) by 10 mm. Determine: (a) the reactions at supports A, B, and C. (b) the maximum bending stress max in the beam. Assume LAB = 4.4 m, LBc=5.2 m. Answers: (a) A = i (b) omax = LAB i B LBC KN, B= MPa. x kN, C = kN.It is not complex, this question for civil engineers expert! A beam is used to support a concentrated load of 12 kN and a distributed load (w). The beam has the following restrains: Fixed support at A, a hinge at B and a roller support at C. If the distributed Load w is 6 kN/m and E is known to be 200 GPa, Determine the following: a. Determine the absolute maximum bending stress in the strut in (MPa). Your solution has to include the shear and bending moment diagram. b. Determine the radius of curvature for member BC in meters. c. It came to your knowledge that the section used has to be changed, calculate the Smin in mm3 for the strut if the allowable stress is 170 MPa. d. If the supports at A and C were changed to pin supports and the hinge at B was removed. How would the maximum bending stress change? Support your claim with numbers. please make sure the answer is correct 100% be accurate and I need clear answer thank you
- Rigid beam AB is supported by three bolts at A and a pin at B. The bolts at A are in double shear and have a diameter of 0.250 in. Assume L = 3.0 ft. If the average shear stress in the bolts cannot exceed 65 ksi, determine the maximum distributed load wmax that can be supported by the structure.Can you answer? be fastly pleaseTwo steel plates are welded together to form an inverted T-beam and are loaded as shown below. Determine the maximum bending stress developed. Also, determine the maximum shear stress at the neutral axis of the cross section. The following Inte Av = 9K Bv = 11K location of centroid = 3.56" above X-Ref Shear diagram Moment diagram 1" x 10" steel plate 1" x 8" steel plate X-reference A 6' 8K 12' 24' 12K 6' B of your work is accurate. Yo ment Mmax = 66K' Vmax 11K Moment of Inertia = 218 inª
- a concentrated load P is acting at the center of the beam having a simple span of 9m. the beam is made up of wide flange with a yield strength of 345 Mpa.the beam has a lateral supports with spacing of 3m. neglect the weight of the beam. Properties of wide flange: d=350mm tw=12mm bf=360mm X=2340 x 10^3 mm^3 tf=18mm what is the minimum unbraced length of the beam to consider it as laterally supported beamRead the question carefully and give me right solution according to the question. The two span beam shown in the figure has spans L1 = 3.3 m and L2 = 5.8 m. The service loads are total dead load of 5.8 kN/m and live load of 6.3 kN/m. If live load is placed to produce maximum negative moment at B, calculate the maximum factored negative bending moment in kN-m.2. A tied column which is subjected to an eccentric load has dimension 300mm x 500 mm which is reinforced with 4D32 as shown. If eccentricity, e = 125 mm, fc’ = 21 MPa, and fy = 414 MPa, compute the following: a. stresses in the steelb. nominal load, Pnc. nominal moment capacity, Mn