The steel truss supports a 6000-lb load. The cross-sectional areas of the members are 0.5 in.2 for AB and 0.75 in.2 for BC. Compute the horizontal and vertical displacement of B using E = 29 x 106 psi. %3D [NOTE: SHOW YOUR FBD AND DEFORMATION DIAGRAM WITH COMPLETE DETAILS] 15 ft 9 ft B 12 ft C 6000 lb

Q: 1. Determine the smallest safe cross-sectional areas of members CD, GD, and GF for the truss shown.…

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A: We have to determine the value of concentrated load at midspan that can be added if uniformly…

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Q: Problem 1: For the shown Truss: Using the method of joints: • Determine the force (magnitude and…

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A: First calculate the member force in BD using the method of sections. Then using the HOOKES  formula…

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Q: 17.17 Member BC of the pin-connected truss has a cross sec- oy = 42 ksi. tion as shown. E = 29 x 10³…

A: Given: E=29000 ksify=42 ksi For 2 C10×30, A=17.64 in2rx=3.43 inry=1.32 in To determine: Load P.

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Q: A) using method of joints  determine the force in members  ED, EC , EF state If in compression or…

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Mechanics of Solids

It is the study of the behavior of solid materials, their characteristics under various circumstances such as variation in external forces, temperature, and other internal factors. It is one of most important study in the field of engineering science, especially chemistry and mechanical engineering. In rigid body, the idealization of the solid body in which deformation is neglected. Deformation is known as the force acting on the solid state system which exerts change in its shape of the body but it continues to be at rest or in a uniform motion but it cannot accelerate. But those solid systems do have elasticity, compressibility and can be bent. This field is very vast since there are wide range of materials around us.