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Determine the concentrated load at midspan that can be added if the uniformly distributed load o is 50 N/m that can be loaded for the beam shown if the allowable bending stress for tension is 80 MPa;, for compression is 130 MPa , for shearing stress is 48 MPa without exceeding deflection limit of L/360. E for steel is 200 GPa. Explain the process. 60 mm 0 = 50 N/m 20 mm 60 mm A D C -20 mm 0.5 m 0.2 m 0.2 m

Determine the concentrated load at midspan that can be added if the uniformly distributed load o is 50 N/m that can be loaded for the beam shown if the allowable bending stress for tension is 80 MPa;, for compression is 130 MPa , for shearing stress is 48 MPa without exceeding deflection limit of L/360. E for steel is 200 GPa. Explain the process. 60 mm 0 = 50 N/m 20 mm 60 mm A D C -20 mm 0.5 m 0.2 m 0.2 m

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Determine the concentrated load at midspan that can be added if the uniformly distributed load o is 50 N/m that can be loaded for the beam shown if the allowable bending stress for tension is 80 MPa;, for compression is 130 MPa , for shearing stress is 48 MPa without exceeding deflection limit of L/360. E for steel is 200 GPa. Explain the process. 60 mm O = 50 N/m 20 mm 60 mm |D B C T-20 mm 0.5 m 0.2 m 0.2 m
Transcribed Image Text:Determine the concentrated load at midspan that can be added if the uniformly distributed load o is 50 N/m that can be loaded for the beam shown if the allowable bending stress for tension is 80 MPa;, for compression is 130 MPa , for shearing stress is 48 MPa without exceeding deflection limit of L/360. E for steel is 200 GPa. Explain the process. 60 mm O = 50 N/m 20 mm 60 mm |D B C T-20 mm 0.5 m 0.2 m 0.2 m
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