A sample of 19 joint specimens of a particular type gave a sample mean proportional limit stress of 8.55 MPa and a sample standard deviation of 0.72 MPa. (a) Calculate and interpret a 95% lower confidence bound for the true average proportional limit stress of all such joints. (Round your answer to two decimal places.) 8.26 MPa
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- A company claims that the mean monthly residential electricity consumption in a certain region is more than 870 kilowatt-hours (kWh). You want to test this claim. You find that a random sample of 69 residential customers has a mean monthly consumption of 900 kWh. Assume the population standard deviation is 122 kWh. At a = 0.05, can you support the claim? Complete parts (a) through (e). (a) Identify Ho and H₂. Choose the correct answer below. OA. Ho: 5900 Ha: >900 (claim) OC. Ho: >870 (claim) Η:15 870 O E. Ho: >900 (claim) H₂900 OB. Ho: H=870 (claim) H₂H870 O D. Ho: H=900 OF. Ho: H≤ 870 H: 900 (claim) (Round to two decimal places as needed.) ⒸA. The critical values are t OB. The critical value is. Identify the rejection region(s). Select the correct choice below. (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. OA. The rejection regions are z 1.64. B. The rejection region…In a seismic hazard analysis, the magnitude of the earthquake (Richter's scale) is modeled with a Type II asymptotic distribution of the largest value. In a certain geographical area, data have been collected for 50 years, and the annual maximum values of the earthquake magnitude have a mean value of 4.0 and a standard deviation of 1.4. It is estimated that an earthquake with a magnitude of 7.0 or more will devastate the region. What is the probability that the annual maximum magnitude will be greater than or equal to 7.0? Compute the same probability if Type I is assumed instead of Type II.Two types of force sensors (A and B) to measure the applied force (Ib) at the tip of a cantilever in a student Lab. The two data sets are shown below: 1. Standard N Deviation Average A 140.2 10.01 12 B 145.5 8.96 14 a. Estimate the interval of the true mean with 95% confidence, using data from sensor A. b. How many more measurements are needed for sensor A to have the same interval with 99% confidence (assume the mean and standard deviation are the same)? c. How many measurements (out of 12) using sensor A to have force greater 142 (randomly sampled)? d. What is the probability to have the true mean force greater 142 using sensor A? e. Determine if there is a difference between the two sensors A and B with 95% of confidence.
- A research study investigated differences between male and female students. Based on the study results, we can assume the population mean and standard deviation for the GPA of male students are µ = 3.5 and σ = 0.5. Suppose a random sample of 100 male students is selected and the GPA for each student is calculated. Find the interval that contains 95.44 percent of the sample means for male students.67°F Cloudy BIG Corporation advertises that its light bulbs have a mean lifetime, u, of 3000 hours. Suppose we have good reason to believe that u is less than 3000 hours and decide to do a statistical test of the claim. We choose a random sample of light bulbs manufactured by BIG and find that the mean lifetime for this sample is 2840 hours and that the sample standard deviation of the lifetimes is 750 hours. Based on this information, complete the parts below. (a) What are the null hypothesis Ho and the alternative hypothesis H₁ that should be used for the test? 0 H₂:0 H₁ (b) Suppose that we decide not to reject the null hypothesis. What sort of error might we be making? (Choose one) ▼ (c) Suppose the true mean lifetime of BIG's light bulbs is 2820 hours. Fill in the blanks to describe a Type II error. A Type II error would be (Choose one) the hypothesis that u is (Choose one) (Choose one) ▼ when, in fact, μ is (Choose one) Explanation Check 9 DALL μχ 0O #0 Españ ? Aa 2022 McGraw Hill…A nutritionist claims that the mean tuna consumption by a person is 3.4 pounds per year. A sample of 90 people shows that the mean tuna consumption by a person is 3.3 pounds per year. Assume the population standard deviation is 1.02 pounds. At α=0.03, can you reject the claim? (a) Identify the null hypothesis and alternative hypothesis. A. H0: μ=3.4 Ha: μ≠3.4 Your answer is correct. B. H0: μ>3.4 Ha: μ≤3.4 C. H0: μ≤3.3 Ha: μ>3.3 D. H0: μ≤3.4 Ha: μ>3.4 E. H0: μ>3.3 Ha: μ≤3.3 F. H0: μ≠3.3 Ha: μ=3.3 (b) Identify the standardized test statistic. z=negative 1.34−1.34 (Round to two decimal places as needed.)
- A company claims that the mean monthly residential electricity consumption in a certain region is more than 870 kilowatt-hours (kWh). You want to test this claim. You find that a random sample of 69 residential customers has a mean monthly consumption of 900 kWh. Assume the population standard deviation is 121 kWh. At a = 0.05, can you support the claim? Complete parts (a) through (e). (a) Identify Ho and H₂. Choose the correct answer below. OA. Ho: >870 (claim) H₂: H≤870 OC. Ho: μ≤900 Ha: >900 (claim) E. Ho: H≤870 H: >870 (claim) OB. Ho: H=900 OA. The rejection region is z> 1.64. OB. The rejection region is z 1.64. H₂: #900 (claim) OD. Ho: H=870 (claim) Ha: 870 OF. Ho: >900 (claim) Ha: HS900 (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) A. The critical value is 1.64. OB. The critical values are t Identify the rejection…A researcher claims that the average wind speed in the desert is less than 18.3 kilometers per hour. A sample of 30 days has an average wind speed of 17 kilometers per hour. The standard deviation of the population is 2.8 kilometers per hour. At a = 0.05, is there enough evidence to reject the claim? a. If a hypothesis testing is to be undertaken, the z Test Value will be equal to:A nutritionist claims that the mean tuna consumption by a person is 3.8 pounds per year. A sample of 70 people shows that the mean tuna consumption by a person is 3.5 pounds per year. Assume the population standard deviation is 1.04 pounds. At α=0.09, can you reject the claim? (a) Identify the null hypothesis and alternative hypothesis. A. H0: μ=3.8 Ha: μ≠3.8 B. H0: μ≠3.5 Ha: μ=3.5 C. H0: μ>3.5 Ha: μ≤3.5 D. H0: μ>3.8 Ha: μ≤3.8 E. H0: μ≤3.5 Ha: μ>3.5 F. H0: μ≤3.8 Ha:μ>3.8 b) Identify the standardized test statistic. z= (Round to two decimal places as needed.) (c) Find the P-value. (d) Decide whether to reject or fail to reject the null hypothesis. A. Reject H0. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.8pounds. B. Reject H0. There is sufficient evidence to reject the claim that mean tuna consumption is equal to…
- A company claims that the mean monthly residential electricity consumption in a certain region is more than 890 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 68 residential customers has a mean monthly consumption of 930 kWh. Assume the population standard deviation is 123 kWh. At a =0.10, can you support the claim? Complete parts (a) through (e). (a) Identify Ho and H. Choose the correct answer below. O A. Ho: uS 930 H:u> 930 (claim) B. Ho: uS 890 H:p> 890 (claim) OC. Ho: u> 930 (claim) O D. Ho: u= 930 H u# 930 (claim) H:us 930 O E. Ho: u= 890 (claim) OF Ho: u>890 (claim) Hus 890 H:u#890 (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) A. The critical value is 1.28. O B. The critical values are t. Identify the rejection region(s). Select the correct choice below. O A. The rejection regions are…A nutritionist claims that the mean tuna consumption by a person is 3.9 pounds per year. A sample of 80 people shows that the mean tuna consumption by a person is 3.8 pounds per year. Assume the population standard deviation is 1.02 pounds. At a = 0.09, can you reject the claim? (a) Identify the null hypothesis and alternative hypothesis. O A. Ho: u>3.8 Ha: μs 3.8 O B. Ho: H#3.8 Ha: μ= 3.8 O C. Ho: Hs3.9 Hai H> 3.9 O D. Ho: H>3.9 O E. Ho: Hs3.8 Ha: H> 3.8 F. Ho: H=3.9 Ha:us3.9 Ha: H#3.9 (b) Identify the standardized test statistic. (Round to two decimal places as needed.)A company claims that the mean monthly residential electricity consumption in a certain region is more than 860 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 60 residential customers has a mean monthly consumption of 880 kWh. Assume the population standard deviation is 123 kWh. At a = 0.05, can you support the claim? Complete parts (a) through (e). (Round to two decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. O A. Fail to reject Ho because the standardized test statistic is in the rejection region. O B. Reject Ho because the standardized test statistic is in the rejection region. O C. Fail to reject Ho because the standardized test statistic is not in the rejection region. O D. Reject Ho because the standardized test statistic is not in the rejection region. (e) Interpret the decision in the context of the original claim. At the 5% significance level, there enough evidence to V the claim that the mean…