A sample of 19 joint specimens of a particular type gave a sample mean proportional limit stress of 8.55 MPa and a sample standard deviation of 0.72 MPa. (a) Calculate and interpret a 95% lower confidence bound for the true average proportional limit stress of all such joints. (Round your answer to two decimal places.) 8.26 MPa
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- more than 880 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 60 residential customers has a mean monthly A company claims that the mean monthly residential electricity consumption in a certain region i consumption of 920 kWh. Assume the population standard deviation is 129 kWh. At a = 0.01, can you support the claim? Complete parts (a) through (e). (a) Identify Ho and H. Choose the correct answer below. O A. Ho: µ= 880 (claim) B. Ho: us 880 H: u#880 H:u> 880 (claim) OC. Ho: u> 920 (claim) O D. Ho: uS920 H:u>920 (claim) H: us920 O E. Ho: u> 880 (claim) ΟΕ H : μ= 920 H:ps 880 Ha:u#920 (claim) (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) O A. The critical values are ± YB. The critical value is 2.33. Identify the rejection region(s). Select the correct choice below. O A. The rejection region is z…A company claims that the mean monthly residential electricity consumption in a certain region is more than 880 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 60 residential customers has a mean monthly consumption of 920 kWh. Assume the population standard deviation is 129 kWh. At a = 0.01, can you support the claim? Complete parts (a) through (e). (a) Identify Ho and H.. Choose the correct answer below. O A. Ho: u= 880 (claim) ΥΒ. H: μs 880 H:u#880 Ha:u> 880 (claim) O C. Ho: u> 920 (claim) Ο D. Hλ: μ5 920 H: us 920 Ha:u>920 (claim) O E. Ho: u> 880 (claim) H:us 880 OF. Ho: H=920 Ha:u#920 (claim) (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) O A. The critical values are + B. The critical value is 2.33 Identify the rejection region(s). Select the correct choice below. O A. The rejection region…A nutritionist claims that the mean tuna consumption by a person is 3.1 pounds per year A sample of 90 people shows that the mean tuna consumption by a person is 2.9 pounds per year. Assume the population standard deviation is 1.19 pounds. At a= 0.05, can you reject the claim? (a) Identify the null hypothesis and alternative hypothesis. O A. Ho H>3.1 Ha µs3.1 B. H, p=3.1 H p#3.1 OC. H, ps3.1 O D. Ho ps2.9 Ha p> 2.9 O E. H, p>2.9 H ps2.9 tents OF H, H 29 H p=2.9 (b) Identify the standardized test statistic. a Library (Round to two decimal places as needed.) Success ple Resources (1,1) More or Success View an example Get more help- Clear all Check answer Help me solve this Copyright 2021 Pearson Education InC. All rights reserved. Terms of Use Privacy Policy Permissions I Contact Us | 64°F A 4 8:30 PM 12/6/202 99+ Type here to search 1005/17 PriSc Insert Fa F9 F10 F12 F6 F7 F5 Num
- 8:50 AA www-awn.aleks.com O DESCRIPTIVE STATISTICS Approximating the standard deviation of a data set. Reyesburg Corporation is contemplating using a new, more expensive glue in the construction of its laminated veneer lumber. Of importance to the company is the variability of the carrying load of the lumber. The company has tested 20 beams using the new glue, recording for each beam the pressure (in pounds per square foot) at which the beam breaks. The data collected are presented in the following histogram: Frequency 920 Carrying load (in pounds per square foot) 900 Based on this histogram, estimate the standard deviation of the sample of 20 carrying loads. Carry your intermediate computations to at least four decimal places, and round your answer to at least one decimal place. (If necessary, consult a list of formulas.) Explanation Check Terms of UseI Privacy I AccessibilityA nutritionist claims that the mean tuna consumption by a person is 3.4 pounds per year. A sample of 90 people shows that the mean tuna consumption by a person is 3.2 pounds per year. Assume the population standard deviation is 1.11 pounds. At a = 0.04, can you reject the claim? (a) Identify the null hypothesis and alternative hypothesis. A. H0: με3.4 Haiµ> 3.4 B. H0: μ>3.4 Hai us3.4 C. H : μ>3.2 Hai us3.2 D. Ho: H#3.2 Haiu= 3.2 E. Ho: µs3.2 Ha: µ> 3.2 F H: μ=3.4 Ha: u#3.4 (b) Identify the standardized test statistic. (Round to two decimal places as needed.)Q15
- 55°F Clear Heights were measured for a random sample of 15 plants grown while being treated with a particular nutrient. The sample mean and sample standard deviation of those height measurements were 50 centimeters and 12 centimeters, respectively. Assume that the population of heights of treated plants is normally distributed with mean u. Based on the sample, can it be concluded that μ is different from 42 centimeters? Use the 0.10 level of significance. Perform a two-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places and round your answers as specified in the table. (If necessary, consult a list of formulas.) (a) State the null hypothesis Ho and the alternative hypothesis H₁. H:0 H₁ : (b) Determine the type of test statistic to use. (Choose one) ▼ (c) Find the value of the test statistic. (Round to three or more decimal places.) 0 (d) Find the p-value. (Round to three or more decimal places.) Jxplanation Check O Search C 3…A company claims that the mean monthly residential electricity consumption in a certain region is more than 870 kilowatt-hours (kWh). You want to test this claim. You find that a random sample of 69 residential customers has a mean monthly consumption of 900 kWh. Assume the population standard deviation is 121 kWh. At a = 0.05, can you support the claim? Complete parts (a) through (e). (a) Identify Ho and H₂. Choose the correct answer below. OA. Ho: >870 (claim) H₂: H≤870 OC. Ho: μ≤900 Ha: >900 (claim) E. Ho: H≤870 H: >870 (claim) OB. Ho: H=900 OA. The rejection region is z> 1.64. OB. The rejection region is z 1.64. H₂: #900 (claim) OD. Ho: H=870 (claim) Ha: 870 OF. Ho: >900 (claim) Ha: HS900 (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) A. The critical value is 1.64. OB. The critical values are t Identify the rejection…A company claims that the mean monthly residential electricity consumption in a certain region is more than 870 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 67 residential customers has a mean monthly consumption of 900 kWh. Assume the population standard deviation is 120 kWh. At a = 0.01, can you support the claim? Complete parts (a) through (e). (a) Identify Ho and Ha. Choose the correct answer below. O A. Ho: µ= 870 (claim) Hạ: H#870 B. Ho: H5870 > 870 (claim) O C. Ho: H> 870 (claim) Ha: u5870 D. Ho: Hs 900 Ha: µ> 900 (claim) O E. Ho: µ> 900 (claim) ΟF Ho: μ= 900 Ha: µ# 900 (claim) Ha: HS 900 (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) A. The critical values are ± B. The critical value is
- A company claims that the mean monthly residential electricity consumption in a certain region is more than 890 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 68 residential customers has a mean monthly consumption of 930 kWh. Assume the population standard deviation is 123 kWh. At a =0.10, can you support the claim? Complete parts (a) through (e). (a) Identify Ho and H. Choose the correct answer below. O A. Ho: uS 930 H:u> 930 (claim) B. Ho: uS 890 H:p> 890 (claim) OC. Ho: u> 930 (claim) O D. Ho: u= 930 H u# 930 (claim) H:us 930 O E. Ho: u= 890 (claim) OF Ho: u>890 (claim) Hus 890 H:u#890 (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) A. The critical value is 1.28. O B. The critical values are t. Identify the rejection region(s). Select the correct choice below. O A. The rejection regions are…A company claims that the mean monthly residential electricity consumption in a certain region is more than 860 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 60 residential customers has a mean monthly consumption of 880 kWh. Assume the population standard deviation is 123 kWh. At a = 0.05, can you support the claim? Complete parts (a) through (e). (Round to two decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. O A. Fail to reject Ho because the standardized test statistic is in the rejection region. O B. Reject Ho because the standardized test statistic is in the rejection region. O C. Fail to reject Ho because the standardized test statistic is not in the rejection region. O D. Reject Ho because the standardized test statistic is not in the rejection region. (e) Interpret the decision in the context of the original claim. At the 5% significance level, there enough evidence to V the claim that the mean…A random sample of 78 eighth grade students' scores on a national mathematics assessment test has a mean score of 275. This test result prompts a state school administrator to declare that the mean score for the state's eighth graders on this exam is more than 270. Assume that the population standard deviation is 33. At a= 0.11, is there enough evidence to support the administrator's claim? Complete parts (a) through (e). Ο D. Ho: μ 270 (b) Find the standardized test statistic z, and its corresponding area. z= 1.34 (Round to two decimal places as needed.) (c) Find the P-value. P-value = 0.0901 (Round to three decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. Reject Ho Fail to reject Ho