You may need to use the appropriate technology to answer this question. Consider the data. X; 3.84 Y₁ 1 2 3 (a) Compute the mean square error using equation s² = MSE = 4 8 6 11 13 places.) 4 5 X X SSE n - 2 (b) Compute the standard error of the estimate using equation s = √ MSE = places.) 1.958 (c) Compute the estimated standard deviation of b, using equation 5b₁ (Round your answer to two decimal places.) SSE n-2 S Σ(x; – x)² (Round your answer to three decimal (Round your answer to three decimal

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### Statistical Analysis Using Regression and Hypothesis Testing

**Data Overview:**

The table of data consists of two variables, \( x_i \) and \( y_i \):

| \( x_i \) | 1 | 2 | 3 | 4 | 5 |
|-----------|---|---|---|---|---|
| \( y_i \) | 4 | 8 | 6 | 11 | 13 |

**Analysis Steps:**

1. **Compute the Mean Square Error (MSE):**
   - Use the formula \( s^2 = \text{MSE} = \dfrac{\text{SSE}}{n-2} \).
   - Answer: 3.84 (incorrect).

2. **Compute the Standard Error of the Estimate:**
   - Use the formula \( s = \sqrt{\text{MSE}} = \sqrt{\dfrac{\text{SSE}}{n-2}} \).
   - Answer: 1.958 (incorrect).

3. **Compute the Estimated Standard Deviation of \( b_1 \):**
   - Use the formula \( s_{b_1} = \dfrac{s}{\sqrt{\sum (x_i - \bar{x})^2}} \).
   - Answer: 0.619 (incorrect).

4. **Use the t-test for Hypothesis Testing (α = 0.05):**
   - Hypotheses:
     - \( H_0: \beta_1 = 0 \)
     - \( H_a: \beta_1 \neq 0 \)
   - Test statistic = 4.038 (incorrect).
   - p-value = 0.0273 (incorrect).

   **Conclusion:**
   - Correct Decision: Reject \( H_0 \). The relationship between \( x \) and \( y \) is significant.

5. **Use the F-test to Confirm Hypothesis at 0.05 Level of Significance:**
   - **ANOVA Table:**

   | Source of Variation | Sum of Squares | Degrees of Freedom | Mean Square | F    | p-value |
   |---------------------|----------------|--------------------|-------------|------|---------|
   | Regression          | 62.5           | 1                  | 62.5        | 16.3 | 0.027   |
   | Error               | 11.5
Transcribed Image Text:### Statistical Analysis Using Regression and Hypothesis Testing **Data Overview:** The table of data consists of two variables, \( x_i \) and \( y_i \): | \( x_i \) | 1 | 2 | 3 | 4 | 5 | |-----------|---|---|---|---|---| | \( y_i \) | 4 | 8 | 6 | 11 | 13 | **Analysis Steps:** 1. **Compute the Mean Square Error (MSE):** - Use the formula \( s^2 = \text{MSE} = \dfrac{\text{SSE}}{n-2} \). - Answer: 3.84 (incorrect). 2. **Compute the Standard Error of the Estimate:** - Use the formula \( s = \sqrt{\text{MSE}} = \sqrt{\dfrac{\text{SSE}}{n-2}} \). - Answer: 1.958 (incorrect). 3. **Compute the Estimated Standard Deviation of \( b_1 \):** - Use the formula \( s_{b_1} = \dfrac{s}{\sqrt{\sum (x_i - \bar{x})^2}} \). - Answer: 0.619 (incorrect). 4. **Use the t-test for Hypothesis Testing (α = 0.05):** - Hypotheses: - \( H_0: \beta_1 = 0 \) - \( H_a: \beta_1 \neq 0 \) - Test statistic = 4.038 (incorrect). - p-value = 0.0273 (incorrect). **Conclusion:** - Correct Decision: Reject \( H_0 \). The relationship between \( x \) and \( y \) is significant. 5. **Use the F-test to Confirm Hypothesis at 0.05 Level of Significance:** - **ANOVA Table:** | Source of Variation | Sum of Squares | Degrees of Freedom | Mean Square | F | p-value | |---------------------|----------------|--------------------|-------------|------|---------| | Regression | 62.5 | 1 | 62.5 | 16.3 | 0.027 | | Error | 11.5
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