K Sub A professor is teaching two sections of a Calculus course, section A and section B. Assume that the test scores are normally distributed. On the midterm, Kelvin in section A scored an 82. The mean of section A was 76 and the standard deviation of the section was 5. Laila, in section B, also scored an 82 but the mean of section B was 75 with a standard deviation of 4. The results from this problem will be used on the next problem so it is a good idea to write them down but you may return to this problem as well. Find the z-score for Kelvin and the z-score for Laila for the midterm of this Calculus course. OA. Kelvin: z=-1.2 and Laila z = -1.75 OB. Kelvin: z=1.2 and Laila z=-1.75 OC. Kelvin z = 1.2 and Laila z=1.75 OD. Kelvin: z=-1.2 and Laila: z = 1.75
K Sub A professor is teaching two sections of a Calculus course, section A and section B. Assume that the test scores are normally distributed. On the midterm, Kelvin in section A scored an 82. The mean of section A was 76 and the standard deviation of the section was 5. Laila, in section B, also scored an 82 but the mean of section B was 75 with a standard deviation of 4. The results from this problem will be used on the next problem so it is a good idea to write them down but you may return to this problem as well. Find the z-score for Kelvin and the z-score for Laila for the midterm of this Calculus course. OA. Kelvin: z=-1.2 and Laila z = -1.75 OB. Kelvin: z=1.2 and Laila z=-1.75 OC. Kelvin z = 1.2 and Laila z=1.75 OD. Kelvin: z=-1.2 and Laila: z = 1.75
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Sub
A professor is teaching two sections of a Calculus course, section A and section B. Assume that the test scores are normally distributed.
On the midterm, Kelvin in section A scored an 82. The mean of section A was 76 and the standard deviation of the section was 5.
Laila, in section B, also scored an 82 but the mean of section B was 75 with a standard deviation of 4.
The results from this problem will be used on the next problem so it is a good idea to write them down but you may return to this problem as well.
Find the z-score for Kelvin and the z-score for Laila for the midterm of this Calculus course.
OA. Kelvin: z=-1.2 and Laila z = -1.75
OB. Kelvin: z=1.2 and Laila z=-1.75
OC. Kelvin z = 1.2 and Laila z=1.75
OD. Kelvin: z=-1.2 and Laila: z = 1.75
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