Ocean currents are important in studies of climate change, as well as ecology studies of dispersal of plankton. Drift bottles areused to study ocean currents in the Pacific near Hawaii, the Solomon Islands, New Guinea, and other islands. Let x represent thenumber of days to recovery of a drift bottle after release and y represent the distance from point of release to point of recovery inkm/100. The following data are representative of one study using drift bottles to study ocean currents.x daysy km/1007214.720335.676325.39419.511.7(a) Verify that Ex = 477, Ey = 86.8, Ex? = 62,029, Ey? = 2028.68, Exy = 11036.6, and r= 0.93853.Ex 477Ey 86.8Ex2 62029Ey2 2028.68Exy 11036.6r 0.93853(b) Use a 1% level of significance to test the claim p > 0. (Use 2 decimal places.)t 8.15critical t 4.54ConclusionO Reject the null hypothesis, there is sufficient evidence that p > 0.O Reject the null hypothesis, there is insufficient evidence that p> 0.O Fail to reject the null hypothesis, there is insufficient evidence that p > 0.O Fail to reject the null hypothesis, there is sufficient evidence that p > 0.(c) Verify that S, = 4.5528, a = 1.4484, and b = 0.1668.S.ab(d) Find the predicted distance (km/100) when a drift bottle has been floating for 90 days. (Use 2 decimal places.)km/100(e) Find a 90% confidence interval for your prediction of part (d). (Use 1 decimal place.)lower limitkm/100upper limitkm/100(f) Use a 1% level of significance to test the claim that B > 0. (Use 2 decimal places.)critical tConclusionO Reject the null hypothesis, there is sufficient evidence that ß > 0.O Reject the null hypothesis, there is insufficient evidence that ß > 0.O Fail to reject the null hypothesis, there is insufficient evidence that 6 > 0.O Fail to reject the null hypothesis, there is sufficient evidence that 6 > 0.(g) Find a 95% confidence interval for ß and interpret its meaning in terms of drift rate. (Use 2 decimal places.)lower limitupper limitInterpretationO For every day of drift, the distance drifted decreases by an amount that falls within the confidence interval.For every day of drift, the distance drifted decreases by an amount that falls outside the confidence interval.For every day of drift, the distance drifted increases by an amount that falls within the confidence interval.O For every day of drift, the distance drifted increases by an amount that falls outside the confidence interval.(h) Consider the following scenario. A sailboat had an accident and radioed a Mayday alert with a given latitude andlongitude just before it sank. The survivors are in a small (but well provisioned) life raft drifting in the part of the PacificOcean under study. After 50 days, how far from the accident site should a rescue plane expect to look? (Usedecimalplaces.)km/100

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The table below shows the number of state-registered automatic weapons and the murder rate for several Northwestern states. xx 11.4 8.5 6.6 3.5 2.7 2.3 2.4 0.4 yy 13.9 11.1 9.4 7.3 6.3 5.8 6.1 4.2 xx = thousands of automatic weaponsyy = murders per 100,000 residentsThis data can be modeled by the equation y=0.86x+3.95.y=0.86x+3.95. Use this equation to answer the following;A) How many murders per 100,000 residents can be expected in a state with 7 thousand automatic weapons?Answer = Round to 3 decimal places.B) How many murders per 100,000 residents can be expected in a state with 9.4 thousand automatic weapons?Answer = Round to 3 decimal places.
A. 72 OB. 67 OC. 76 O D. 73 12 Find the mean, median, and mode of the data. Heights of Students in Class 60 62 64 66 68 70 72 74 76 78 80 82 Inches O A. x = 70; median = 67; mode= 69 OB. X 70.3; median = 69; mode = 68 OC. x=70; median = 69; mode = 67 OD. x 70.1; median = 69; mode = 68 67 67
type not wright thx
a dataset with a mean of 60 and a standard deviation of 8, how many observations are expected to fall betweer standard deviation and +1 standard deviation of the mean in a normally distributed set of data?
The table below shows the number of state-registered automatic weapons and the murder rate for several Northwestern states. xx 11.8 8.6 7.1 3.9 2.5 2.6 2.4 0.4 yy 14.3 11.5 9.8 7.6 6.2 6.5 6.4 4.1 xx = thousands of automatic weaponsyy = murders per 100,000 residentsThis data can be modeled by the equation y=0.86x+4.07.y=0.86x+4.07. Use this equation to answer the following; Special Note: I suggest you verify this equation by performing linear regression on your calculator.A) How many murders per 100,000 residents can be expected in a state with 3 thousand automatic weapons?Answer = Round to 3 decimal places.B) How many murders per 100,000 residents can be expected in a state with 4.1 thousand automatic weapons?Answer = Round to 3 decimal places.
Following this week's empirical application, the scatter plot below plots average rain in a city (vertical axis) against average PM 10 levels in a city (horizontal axis). Based on this figure, what appears to be true? Average Rain in a City u Rain vs Pollution by City 120 Average PM10 in a City 160 Cities with more rain tend to have less pollution O Cities with less pollution tend to have less rain O There is no statistical relationship between rain and pollution O Cities with more rain tend to have more pollution
Americium 241 (241Am) is a radioactive material used in the manufacture of smoke detectors. The article "Retention and Dosimetry of Injected 241Am in Beagles"t described a study in which 55 beagles were injected with a dose of 241Am (proportional to each animal's weight). Skeletal retention of 241 Am (in microcuries per kilogram) was recorded for each beagle, resulting in the following data. 0.196 0.451 0.498 0.411 0.324 0.190 0.489 0.300 0.346 0.448 0.188 0.399 0.305 0.304 0.287 0.243 0.334 0.299 0.292 0.419 0.236 0.315 0.447 0.585 0.291 0.186 0.393 0.419 0.335 0.332 0.292 0.375 0.349 0.324 0.301 0.33 0.408 0.399 0.303 0.318 0.468 0.441 0.306 0.367 0.345 0.428 0.345 0.412 0.337 0.353 0.357 0.320 0.354 0.361 0.329 A USE SALT (a) Construct a frequency distribution for these data. Commute Time Frequency 0.15 to <0.20 10 0.20 to <0.25 11 0.25 to <0.30 48 0.30 to <0.35 0.35 to <0.40 0.40 to <0.45 0.45 to <0.50 0.50 to <0.55 0.55 to <0.60
Give the mode for following GFDT. (Recall, there is a definition for the mode appropriate for GFDTS.) Data Frequency 40 - 44 14 45 - 49 21 50 - 54 12 55 - 59 10 60 - 64 8 65 - 69 6 70 - 74 75 - 79 1 80 - 84 1 mode = %3D
Please use the accompanying Excel data set or accompanying Text file data set when completing the following exercise. An article in the Journal of Sound and Vibration (Vol. 151, 1991, pp. 383-394) described a study investigating the relationship between noise exposure and hypertension. The following data are representative of those reported in the article. y x y x 1 60 5 85 O 63 4 89 1 65 6 90 2 70 8 90 5 70 4 90 1 70 5 90 4 80 7 94 6 90 9 100 2 80 7 100 3 80 6 100 Fit a linear regression model relating blood pressure rise in millimeters of mercury (y) to sound pressure level in decibels (x) using least squares. (2) Drawa scatter diagram of y versus x (using statistical software). Does a simple linear regression model seem reasonable in this situation? (b) Calculate the least squares estimate of the slope. B = (Round your answer to 3 decimal places.) (c) Calculate the least squares estimate of the intercept. B, = i (Round your answer to 3 decimal places.)
The table below shows the number of state-registered automatic weapons and the murder rate for several Northwestern states. xx 11.6 8.3 7.1 3.9 2.7 2.5 2.5 0.3 yy 13.6 10.8 10.3 7.3 6 6.3 6 4.5 xx = thousands of automatic weaponsyy = murders per 100,000 residentsThis data can be modeled by the equation ˆy=0.82x+4.09.y^=0.82x+4.09. Use this equation to answer the following.A) How many murders per 100,000 residents can be expected in a state with 4 thousand automatic weapons?Answer = Round to 3 decimal places.B) How many murders per 100,000 residents can be expected in a state with 3.2 thousand automatic weapons?Answer = Round to 3 decimal places.
Suppose an oceanographer monitors the daily salinity of a particular ocean in relation to the temperature of the water. The oceanographer plots the data with temperature, in degrees Celsius (°C), along the horizontal axis and salinity, in parts per thousand (ppt), along the vertical axis. Select the true statement about the data point identified by the arrow. An ocean temperature of 21 °C causes the salinity to be 29 ppt. The predicted salinity is 29 ppt when the ocean temperature for the day is 21 °C. An ocean temperature of 29 °C corresponds to a salinity level of 21 ppt. The observed salinity is 29 ppt when the ocean temperature for the day is 21 °C. There is no relationship between the temperature of the ocean on a given day and salinity.
The table below shows the number of state-registered automatic weapons and the murder rate for several Northwestern states. xx 11.5 8.5 7 3.7 2.7 2.5 2.6 0.8 yy 13.8 11.1 10.1 7.2 6.4 6.1 6.1 4.8 xx = thousands of automatic weaponsyy = murders per 100,000 residentsThis data can be modeled by the equation ˆy=0.85x+4.05.y^=0.85x+4.05. Use this equation to answer the following.A) How many murders per 100,000 residents can be expected in a state with 6.7 thousand automatic weapons?Answer = Round to 3 decimal places.B) How many murders per 100,000 residents can be expected in a state with 3.3 thousand automatic weapons?Answer = Round to 3 decimal places.

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