A company claims that the mean monthly residential electricity consumption in a certain region is more than 890 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 64 residential customers has a mean monthly consumption of 920 kWh. Assume the population standard deviation is 130 kWh. At α=0.05, can you support the claim? Complete parts (a) through (e). (a) Identify H0 and Ha. Choose the correct answer below. A. H0: μ>920 (claim) Ha: μ≤920 B. H0: μ>890 (claim) Ha: μ≤890 C. H0: μ=920 Ha: μ≠920 (claim) D. H0: μ≤890 Ha: μ>890 (claim) E. H0: μ=890 (claim) Ha: μ≠890 F. H0: μ≤920 Ha: μ>920 (claim) (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) A. The critical value is . B. The critical values are ± . Identify the rejection region(s). Select the correct choice below. A. The rejection region is z<1.64. B. The rejection regions are z<−1.64 and z>1.64. C. The rejection region is z>1.64. (c) Find the standardized test statistic. Use technology. The standardized test statistic is z= (Round to two decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. A. Fail to reject H0 because the standardized test statistic is in the rejection region. B. Reject H0 because the standardized test statistic is in the rejection region. C. Fail to reject H0 because the standardized test statistic is not in the rejection region. D.Reject H0 because the standardized test statistic is not in the rejection region.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A company claims that the mean monthly residential electricity consumption in a certain region is more than 890 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 64 residential customers has a mean monthly consumption of 920 kWh. Assume the population standard deviation is 130 kWh. At α=0.05, can you support the claim? Complete parts (a) through (e).

(a) Identify H0 and Ha. Choose the correct answer below.

A. H0: μ>920 (claim) Ha: μ≤920

B. H0: μ>890 (claim) Ha: μ≤890

C. H0: μ=920 Ha: μ≠920 (claim)

D. H0: μ≤890 Ha: μ>890 (claim)

E. H0: μ=890 (claim) Ha: μ≠890

F. H0: μ≤920 Ha: μ>920 (claim)

(b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology.

(Round to two decimal places as needed.)

A. The critical value is .

B. The critical values are ± .

Identify the rejection region(s). Select the correct choice below.

A. The rejection region is z<1.64.

B. The rejection regions are z<−1.64 and z>1.64.

C. The rejection region is z>1.64.

The standardized test statistic is z=

(Round to two decimal places as needed.)

(d) Decide whether to reject or fail to reject the null hypothesis.

A. Fail to reject H0 because the standardized test statistic is in the rejection region.

B. Reject H0 because the standardized test statistic is in the rejection region.

C. Fail to reject H0 because the standardized test statistic is not in the rejection region.

D.Reject H0 because the standardized test statistic is not in the rejection region.

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