A survey collected data from a random sample of 121 people living in Jade city. The sample average of the distance people travel to reach theirworkplaces (Y) is 23.28 km and the standard deviation (sy) is 7.48 km.The standard error of the sample average of the distance people travel to reach their workplaces is 68 km.(Round your answer to two decimal places.)Let μy denote the mean of the distance all the people in Jade city travel to reach their workplaces.The p-value of the test Ho: #y #22 km vs. H₁: Hy #22 km is(Round your answer to two decimal places.)

Sample size, Sample average, Sample standard deviation,

Answered: A survey collected data from a random…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A vendor converts the weights on the packages she sends from pounds to kilograms (1 kg ≈ 2.20 lb). The mean weight of the package was 21 lb with standard deviation of 0.31 lb. After repackaging (converting units), the mean becomes kg (round your answer to 2 decimal places), and the standard deviation becomes kg (round your answer to 2 decimal places).
Hope to answer this accordingly.
Assume that the SAT test scores are normally distributed with a mean score of 1200 and a standard deviation of 150. ACT test scores are normally distributed with a mean score of 22 and a standard deviation of 3 Mike scored 1250 on the SAT. What proportion of all test takers did Mike score higher than? If Mike scored a 1250 on the SAT and Jes scored a 26 on the ACT, then who's score is relatively better?
Test scores for a Statistics class have a mean of 81 with a standard deviation of 4. Test scores for a calculus class had a mean of 75 with a standard deviation of 3.5. Suppose a student gets an 87 on the statistics test andan 86 on the calculus test. Calculate the z-scores for each test. On which test did the student perform better relative to the other students in the class.
In a survey, the mean weight of 1032 rats was calculated to be 132 gr. The standard deviation of the observation was found to be s=3 gr. Determine at least how many of the surveyed rats have a weight between 124.5 and 139.5 gr.
Round each z-score to the nearest hundredth. A data set has a mean of x = 213 and a standard deviation of 48. Find the z-score for each of the following. (a) x = 200 (b) x = 224 (c) x = 300 (d) x = 100
Sam and Peter are classmates. In an examination, Sam gets 75 marks and Peter gets 89 marks. It is known that the standard normal score of Sam's marks is 0, z(Sam) = 0 and the standard normal score of Peter's marks is 1.75, z(Peter) = 1.75. Find the standard deviation of the examination marks.
A standardized exam's scores are normally distributed. In a recent year, the mean test score was 1466 and the standard deviation was 315. The test scores of four students selected at random are 1890, 1210, 2200, and 1340. Find the z-scores that correspond to each value and determine whether any of the values are unusual. The Z-score for 1890 is. (Round to two decimal places as needed.).
Use z scores to compare the given values. The tallest living man at one time had a height of 238 cm. The shortest living man at that time had a height of 142.4 cm. Heights of men at that time had a mean of 175.45 cm and a standard deviation of 5.59 cm. Which of these two men had the height that was more extreme? ... Since the z score for the tallest man is z = 0 and the z score for the shortest man is z = the man had the height that was Im- more extreme. (Round to two decimal places.) shortest tallest
Use z scores to compare the given values. The tallest living man at one time had a height of 228 cm. The shortest living man at that time had a height of 131.9 cm. Heights of men at that time had a mean of 174.11 cm and a standard deviation of 5.72 cm. Which of these two men had the height that was more extreme? Since the z score for the tallest man is z = (Round to two decimal places.) and the z score for the shortest man is z = the man had the height that was more extreme.
Suppose that a category of world class runners are known to run a marathon (26 miles) in an average of 146 minutes with a standard deviation of 13minutes. Consider 49 of the races.Let X = the average of the 49 races. Find the 60th percentile for the average of these 49 marathons. (Round your answer to two decimal places.)min
The scores on the Accuplacer test and High School GPAs are normally distributed.The Accuplacer test had a mean of 40 and a standard deviation of 8.High School GPAs had a mean of 3 and a standard deviation of 0.1.What high school GPA do you need to equal a score of 48 on the Accuplacer test?Give answer to two decimal places.

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