A company claims that the mean monthly residential electricity consumption in a certain region is more than 870 kiloWatt-hours (kWh). You want to test this claim.You find that a random sample of 60 residential customers has a mean monthly consumption of 910 kWh. Assume the population standard deviation is 123 kWh.At a= 0.10, can you support the claim? Complete parts (a) through (0).(a) Identify Ho and H Choose the correct answer below.O A. Ho: >870 (claim)Hus870O B. Ho: >910 (claim)Hus910OC. Ho: =870 (claim)H#870OD. Ho S91oH>910 (claim)OE Ho: u=910Hu#910 (claim)OF. Ho: us870Hp>870 (claim)(b) Find the critical value(s) and identify the rejection region(s). Select the correct choiceand fil in the answer box within your choice. Use technology.(Round to two decimal places as needed.)OA The critical value is.O B. The critical values are .Identify the rejection region(s). Select the correct choice below.OA The rejection region is z<1.28.O B. The rejection regions are z< -1.28 and z>1.28.OC. The rejection region is z>1.28.(c) Find the standardized test statistic. Use technologyThe standardized test statistic is z=(Round to two decimal places as needed.)

Given that Sample size n =60 Sample mean =910 Population standard deviation =123

Answered: A company claims that the mean monthly…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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