A company claims that the mean monthly residential electricity consumption in a certain region is more than 860kilowatt-hours (kWh). You want to test this claim. You find that a random sample of 69 residential customers has almean monthly consumption of 880 kWh. Assume the population standard deviation is 120 kWh. At a = 0.01, can yousupport the claim? Complete parts (a) through (e).(a) Identify Ho and H₂. Choose the correct answer below.OA. Ho: ≤880Ha: >880 (claim)c. Ho: s860Ha: >860 (claim)OE. Ho: >860 (claim)H₂H860OB. Ho: H>880 (claim)H:Hs880OD. Ho: H=860 (claim)Ha: 860OF. Ho: 880H₂H880 (claim)(b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answerbox within your choice. Use technology.(Round to two decimal places as needed.).OA. The critical values are ±OB. The critical value is

Given n=69 X-bar=880 Mu=860 Alpha=0.01 Standard deviations=120

Answered: A company claims that the mean monthly…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You want to obtain a sample to estimate a population mean. Based on previous evidence, you believe the population standard deviation is approximately σ=72.1σ=72.1. You would like to be 99% confident that your estimate is within 2 of the true population mean. How large of a sample size is required?
I need you guys help with the attached.
nutritionist claims that the mean tuna consumption by a person is 3.4 pounds per year. A sample of 90 people shows that the mean tuna consumption by a person is 3.3 pounds per year. Assume the population standard deviation is 1.02 pounds. At α=0.03, can you reject the claim? (a) Identify the null hypothesis and alternative hypothesis. A. H0: μ=3.4 Ha: μ≠3.4 Your answer is correct. B. H0: μ>3.4 Ha: μ≤3.4 C. H0: μ≤3.3 Ha: μ>3.3 D. H0: μ≤3.4 Ha: μ>3.4 E. H0: μ>3.3 Ha: μ≤3.3 F. H0: μ≠3.3 Ha: μ=3.3 (b) Identify the standardized test statistic. z=negative 0.93−0.93 (Round to two decimal places as needed.) (c) Find the P-value. 0.3520.352 (Round to three decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis.
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