### Hypothesis Testing for Mean Tuna ConsumptionA nutritionist claims that the mean tuna consumption by a person is 3.5 pounds per year. A sample of 90 people shows a mean tuna consumption of 3.3 pounds per year. It is given that the population standard deviation is 1.02 pounds. At a significance level of α = 0.08, can you reject the claim?#### (a) Identify the Null Hypothesis and Alternative HypothesisThe given options for hypotheses are:- **A**. $ H_0: \mu \leq 3.5 $; $ H_a: \mu > 3.5 $- **B**. $ H_0: \mu > 3.5 $; $ H_a: \mu \leq 3.5 $- **C**. $ H_0: \mu \neq 3.3 $; $ H_a: \mu = 3.3 $- **D**. $ H_0: \mu = 3.5 $; $ H_a: \mu \neq 3.5 $ (Correct)- **E**. $ H_0: \mu \leq 3.3 $; $ H_a: \mu > 3.3 $- **F**. $ H_0: \mu > 3.3 $; $ H_a: \mu \leq 3.3 $The correct hypothesis statement is:- **Null Hypothesis ($ H_0 $)**: $ \mu = 3.5 $- **Alternative Hypothesis ($ H_a $)**: $ \mu \neq 3.5 $#### (b) Identify the Standardized Test StatisticTo calculate the z-score, the formula is:\[z = \frac{\bar{x} - \mu}{\sigma/\sqrt{n}}\]Where:- $ \bar{x} $ = Sample mean = 3.3- $ \mu $ = Population mean under null hypothesis = 3.5- $ \sigma $ = Population standard deviation = 1.02- $ n $ = Sample size = 90Calculate the z-score and fill in the provided box, rounding to two decimal places.\[ z = \frac{3.3 -

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Given information- Population mean, μ = 3.5 pounds Sample mean, x-bar = 3.3 pounds Sample size, n =…

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A nutritionist claims that the mean tuna consumption by a person is 3.5 pounds per year. A sample of 90 people shows that the mean tuna consumption by a person is 3.3 pounds per year. Assume the population standard deviation is 1.02 pounds. At a = 0.08, can you reject the claim? (a) Identify the null hypothesis and alternative hypothesis. Ο Α. H : μS 3.5 Ha: u> 3.5 О В. Но: > 3.5 Ha: us3.5 С. Но: и#3.3 Ha: u = 3.3 D. Ho: μ= 3.5 Ο Ε. Hρ: μ5 3.3 Ha: u> 3.3 O F. Ho: u> 3.3 Ha: us3.3 Ha: u#3.5 (b) Identify the standardized test statistic. z= (Round to two decimal places as needed.)

A nutritionist claims that the mean tuna consumption by a person is 3.5 pounds per year. A sample of 90 people shows that the mean tuna consumption by a person is 3.3 pounds per year. Assume the population standard deviation is 1.02 pounds. At a = 0.08, can you reject the claim? (a) Identify the null hypothesis and alternative hypothesis. Ο Α. H : μS 3.5 Ha: u> 3.5 О В. Но: > 3.5 Ha: us3.5 С. Но: и#3.3 Ha: u = 3.3 D. Ho: μ= 3.5 Ο Ε. Hρ: μ5 3.3 Ha: u> 3.3 O F. Ho: u> 3.3 Ha: us3.3 Ha: u#3.5 (b) Identify the standardized test statistic. z= (Round to two decimal places as needed.)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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