A company claims that the mean monthly residential electricity consumption in a certain region is more than 870 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 67 residential customers has a mean monthly consumption of 900 kWh. Assume the population standard deviation is 120 kWh. At a = 0.01, can you support the claim? Complete parts (a) through (e). (a) Identify Ho and Ha. Choose the correct answer below. O A. Ho: µ= 870 (claim) Ho: u5870 Ha: H> 870 (claim) Hai H#870 O C. Ho: H> 870 (claim) Ha: HS870 Ο D. H : μs 900 Ha:H> 900 (claim) ΟF H0: μ= 900 Ha:H#900 (claim) O E. Ho: H> 900 (claim) Ha: us 900 (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) O A. The critical values are ± O B. The critical value is
A company claims that the mean monthly residential electricity consumption in a certain region is more than 870 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 67 residential customers has a mean monthly consumption of 900 kWh. Assume the population standard deviation is 120 kWh. At a = 0.01, can you support the claim? Complete parts (a) through (e). (a) Identify Ho and Ha. Choose the correct answer below. O A. Ho: µ= 870 (claim) Ho: u5870 Ha: H> 870 (claim) Hai H#870 O C. Ho: H> 870 (claim) Ha: HS870 Ο D. H : μs 900 Ha:H> 900 (claim) ΟF H0: μ= 900 Ha:H#900 (claim) O E. Ho: H> 900 (claim) Ha: us 900 (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) O A. The critical values are ± O B. The critical value is
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
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Chapter1: Starting With Matlab
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Problem 1P
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![**Educational Website Content: Hypothesis Testing for Mean Monthly Electricity Consumption**
A company claims that the mean monthly residential electricity consumption in a certain region is more than 870 kilowatt-hours (kWh). You want to test this claim. You find that a random sample of 67 residential customers has a mean monthly consumption of 900 kWh. Assume the population standard deviation is 120 kWh. At a significance level of α = 0.01, can you support the claim? Complete parts (a) through (e).
### (a) Identify H₀ and Hₐ.
Choose the correct answer below:
- **A.** H₀: μ = 870 (claim)
Hₐ: μ ≠ 870
- **B.** H₀: μ ≤ 870
Hₐ: μ > 870 (claim) ✔️
- **C.** H₀: μ > 870 (claim)
Hₐ: μ ≤ 870
- **D.** H₀: μ ≤ 900
Hₐ: μ > 900 (claim)
- **E.** H₀: μ > 900 (claim)
Hₐ: μ ≤ 900
- **F.** H₀: μ = 900
Hₐ: μ ≠ 900 (claim)
### (b) Find the critical value(s) and identify the rejection region(s).
Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.)
- **A.** The critical values are ± ☐
- **B.** The critical value is ☐
**Note:** To complete this section, use statistical software or tables to find the critical value(s) for a right-tailed test with α = 0.01.
---
This exercise involves hypothesis testing where the null hypothesis (H₀) represents the assumption that there is no effect or no difference, and the alternative hypothesis (Hₐ) represents the claim that there is an effect or a difference. In this context, it helps determine if the mean monthly electricity consumption is indeed more than 870 kWh.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa332979b-3709-48a2-942a-205e2ae2d053%2Fec05e00a-a9e8-4005-ab05-9e09a0f8e01b%2Fd0yh0p_processed.png&w=3840&q=75)
Transcribed Image Text:**Educational Website Content: Hypothesis Testing for Mean Monthly Electricity Consumption**
A company claims that the mean monthly residential electricity consumption in a certain region is more than 870 kilowatt-hours (kWh). You want to test this claim. You find that a random sample of 67 residential customers has a mean monthly consumption of 900 kWh. Assume the population standard deviation is 120 kWh. At a significance level of α = 0.01, can you support the claim? Complete parts (a) through (e).
### (a) Identify H₀ and Hₐ.
Choose the correct answer below:
- **A.** H₀: μ = 870 (claim)
Hₐ: μ ≠ 870
- **B.** H₀: μ ≤ 870
Hₐ: μ > 870 (claim) ✔️
- **C.** H₀: μ > 870 (claim)
Hₐ: μ ≤ 870
- **D.** H₀: μ ≤ 900
Hₐ: μ > 900 (claim)
- **E.** H₀: μ > 900 (claim)
Hₐ: μ ≤ 900
- **F.** H₀: μ = 900
Hₐ: μ ≠ 900 (claim)
### (b) Find the critical value(s) and identify the rejection region(s).
Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.)
- **A.** The critical values are ± ☐
- **B.** The critical value is ☐
**Note:** To complete this section, use statistical software or tables to find the critical value(s) for a right-tailed test with α = 0.01.
---
This exercise involves hypothesis testing where the null hypothesis (H₀) represents the assumption that there is no effect or no difference, and the alternative hypothesis (Hₐ) represents the claim that there is an effect or a difference. In this context, it helps determine if the mean monthly electricity consumption is indeed more than 870 kWh.
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