A company claims that the mean monthly residential electricity consumption in a certain region is more than 880 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 60 residential customers has a mean monthly consumption of 920 kWh. Assume the population standard deviation is 129 kWh. At a = 0.01, can you support the claim? Complete parts (a) through (e). H: ps 880 Ha: u#920 (claim) (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) O A. The critical values are + & B. The critical value is 2.33. Identify the rejection region(s). Select the correct choice below. O A. The rejection region is z<2.33. YB. The rejection region is z>2.33. O C. The rejection regions are z< -2.33 and z>2.33. (c) Find the standardized test statistic. Use technology. The standardized test statistic is z= 2.40. (Round to two decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. O A. Fail to reject Ho because the standardized test statistic is in the rejection region. O B. Reject H, because the standardized test statistic is in the rejection region. O C. Reject H, because the standardized test statistic is not in the rejection region. O D. Fail to reject H, because the standardized test statistic is not in the rejection region.
A company claims that the mean monthly residential electricity consumption in a certain region is more than 880 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 60 residential customers has a mean monthly consumption of 920 kWh. Assume the population standard deviation is 129 kWh. At a = 0.01, can you support the claim? Complete parts (a) through (e). H: ps 880 Ha: u#920 (claim) (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) O A. The critical values are + & B. The critical value is 2.33. Identify the rejection region(s). Select the correct choice below. O A. The rejection region is z<2.33. YB. The rejection region is z>2.33. O C. The rejection regions are z< -2.33 and z>2.33. (c) Find the standardized test statistic. Use technology. The standardized test statistic is z= 2.40. (Round to two decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. O A. Fail to reject Ho because the standardized test statistic is in the rejection region. O B. Reject H, because the standardized test statistic is in the rejection region. O C. Reject H, because the standardized test statistic is not in the rejection region. O D. Fail to reject H, because the standardized test statistic is not in the rejection region.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:A company claims that the mean monthly residential electricity consumption in a certain region is more than 880 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 60 residential customers has a mean monthly
consumption of 920 kWh. Assume the population standard deviation is 129 kWh. At a = 0.01, can you support the claim? Complete parts (a) through (e).
H: us 880
Ha: u#920 (claim)
(b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology.
(Round to two decimal places as needed.)
O A. The critical values are +
& B. The critical value is 2.33
Identify the rejection region(s). Select the correct choice below.
O A. The rejection region is z<2.33.
Y B. The rejection region is z>2.33.
O C. The rejection regions are z< -2.33 and z>2.33.
(c) Find the standardized test statistic. Use technology.
The standardized test statistic is z= 2.40.
(Round to two decimal places as needed.)
(d) Decide whether to reject or fail to reject the null hypothesis.
O A. Fail to reject Ho because the standardized test statistic is in the rejection region.
O B. Reject H, because the standardized test statistic is in the rejection region.
O C. Reject H, because the standardized test statistic is not in the rejection region.
O D. Fail to reject H, because the standardized test statistic is not in the rejection region.
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