A researcher compares two compounds (1 and 2) used in the manufacture of car tires that are designed to reduce braking distances for SUVs equipped with the tires. SUVs equipped with tires using compound 1 have a mean braking distance of 7777 feet and a standard deviation of 12.812.8 feet. SUVs equipped with tires using compound 2 have a mean braking distance of 8585 feet and a standard deviation of 5.35.3 feet. Suppose that a sample of 3333 braking tests are performed for each compound. Using these results, test the claim that the braking distance for SUVs equipped with tires using compound 1 is shorter than the braking distance when compound 2 is used. Let μ1μ1 be the true mean braking distance corresponding to compound 1 and μ2μ2 be the true mean braking distance corresponding to compound 2. Use the 0.10.1 level of significance. Step 1 of 4 : State the null and alternative hypotheses
A researcher compares two compounds (1 and 2) used in the manufacture of car tires that are designed to reduce braking distances for SUVs equipped with the tires. SUVs equipped with tires using compound 1 have a mean braking distance of 7777 feet and a standard deviation of 12.812.8 feet. SUVs equipped with tires using compound 2 have a mean braking distance of 8585 feet and a standard deviation of 5.35.3 feet. Suppose that a sample of 3333 braking tests are performed for each compound. Using these results, test the claim that the braking distance for SUVs equipped with tires using compound 1 is shorter than the braking distance when compound 2 is used. Let μ1μ1 be the true mean braking distance corresponding to compound 1 and μ2μ2 be the true mean braking distance corresponding to compound 2. Use the 0.10.1 level of significance.
State the null and alternative hypotheses for the test.
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