A researcher compares two compounds (1 and 2) used in the manufacture of car tires that are designed to reduce braking distances for SUVs equipped with the tires. The mean braking distance for SUVS equipped with tires made with compound 1 is 50 feet, with a population standard deviation of 12.4. The mean braking distance for SUVs equipped with tires made with compound 2 is 54 feet, with a population standard deviation of 13.0. Suppose that a sample of 71 braking tests are performed for each compound. Using these results, test the claim that the braking distance for SUVs equipped with tires using compound 1 is shorter than the braking distance when compound 2 is used. Let μ₁ be the true mean braking distance corresponding to compound 1 and μ₂ be the true mean braking distance corresponding to compound 2. Use the 0.1 level of significance. Step 2 of 5: Compute the value of the test statistic. Round your answer to two decimal places.

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A researcher compares two compounds (1 and 2) used in the manufacture of car tires that are designed to reduce braking distances for SUVs equipped with the tires. The mean braking distance for SUVs equipped with tires made with compound 1 is 50 feet, with a population standard deviation of 12.4. The mean braking distance for SUVs equipped with tires made with compound 2 is 54 feet, with a population standard deviation of 13.0. Suppose that a sample of 7171 braking tests are performed for each compound. Using these results, test the claim that the braking distance for SUVs equipped with tires using compound 1 is shorter than the braking distance when compound 2 is used. Let μ1 be the true mean braking distance corresponding to compound 1 and μ2 be the true mean braking distance corresponding to compound 2. Use the 0.1 level of significance.

Step 2 of 5 :  

Compute the value of the test statistic. Round your answer to two decimal places.

A researcher compares two compounds (1 and 2) used in the manufacture of car tires that are designed
to reduce braking distances for SUVs equipped with the tires. The mean braking distance for SUVS
equipped with tires made with compound 1 is 50 feet, with a population standard deviation of 12.4.
The mean braking distance for SUVs equipped with tires made with compound 2 is 54 feet, with a
population standard deviation of 13.0. Suppose that a sample of 71 braking tests are performed for
each compound. Using these results, test the claim that the braking distance for SUVs equipped with
tires using compound 1 is shorter than the braking distance when compound 2 is used. Let μ₁ be the
true mean braking distance corresponding to compound 1 and μ₂ be the true mean braking distance
corresponding to compound 2. Use the 0.1 level of significance.
Step 2 of 5: Compute the value of the test statistic. Round your answer to two decimal places.
Transcribed Image Text:A researcher compares two compounds (1 and 2) used in the manufacture of car tires that are designed to reduce braking distances for SUVs equipped with the tires. The mean braking distance for SUVS equipped with tires made with compound 1 is 50 feet, with a population standard deviation of 12.4. The mean braking distance for SUVs equipped with tires made with compound 2 is 54 feet, with a population standard deviation of 13.0. Suppose that a sample of 71 braking tests are performed for each compound. Using these results, test the claim that the braking distance for SUVs equipped with tires using compound 1 is shorter than the braking distance when compound 2 is used. Let μ₁ be the true mean braking distance corresponding to compound 1 and μ₂ be the true mean braking distance corresponding to compound 2. Use the 0.1 level of significance. Step 2 of 5: Compute the value of the test statistic. Round your answer to two decimal places.
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