A researcher compares two compounds (1 and 2) used in the manufacture of car tires that are designed to reduce braking distances for SUVS equipped with the tires.The mean braking distance for SUVS equipped with tires made with compound 1 is 70 feet, with a population standard deviation of 11.6. The mean braking distance forSUVs equipped with tires made with compound 2 is 77 feet, with a population standard deviation of 9.8. Suppose that a sample of 35 braking tests are performed foreach compound. Using these results, test the claim that the braking distance for SUVS equipped with tires using compound 1 is shorter than the braking distance whencompound 2 is used. Let μ₁ be the true mean braking distance corresponding to compound 1 and μ₂ be the true mean braking distance corresponding to compound 2.Use the 0.05 level of significance.Step 3 of 5: Find the p-value associated with the test statistic. Round your answer to four decimal places.AnswerHow to enter your answer (opens in new window)p = ||TTablesKeypadKeyboard ShortcutsPrevious Step Answers

p value is less than 0.05Explanation:

Answered: A researcher compares two compounds (1…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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To compare the dry braking distances from 30 to 0 miles per hour for two makes of automobiles, a safety engineer conducts braking tests for 35 models of Make A and 35 models of Make B. The mean braking distance for Make A is 43 feet. Assume the population standard deviation is 4.6 feet. The mean braking distance for Make B is 46 feet. Assume the population standard deviation is 4.5 feet. At α=0.10, can the engineer support the claim that the mean braking distances are different for the two makes of automobiles? Assume the samples are random and independent, and the populations are normally distributed. The critical value(s) is/are Find the standardized test statistic z for μ1−μ2.
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