a Can we conclude that there is a difference in the mean measurements between the two methods?
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Q: A coin-operated drink machine was designed to discharge a mean of 8 fluid ounces of coffee per cup.…
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Two methods have been developed to determine the nickel content of steel. In a sample of five replications of the first method on a certain kind of steel, the average measurement (in percent) was 5= 3.16 and the
standard deviation was s, = 0,042. The average of seven replications of
the second method was y = 3.24 and the standard deviation was s, = 0,048.
Assume that it is known that the population variances are nearly equal.
a Can we conclude that there is a difference in the mean measurements between the two methods?
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- 1. (A.) The lifetimes of a certain brand of battery are normally distributed with mean of 100 hours and standard deviation of 5 hours. The 95th percentile of battery lifetimes is: į. 1.645 ii. -1.645 iii. 108.23 iv. 91.775 (B.) The reaction time it takes a driver to react to the brake lights on a decelerating vehicle is normally distributed with mean of 1.3 seconds and standard deviation of 0.5 seconds. We wish to calculate the probability that the reaction time of a driver is between 1.00 and 1.90 seconds. The area under the standard normal curve is: į. 0.3893 ii. 0.2743 iii. 0.6107 iv. 0.8849 (C.) A survey indicated that children between ages of 2 and 5 years watch on average 24 hours of TV per week. The number of hours of TV watching per week by this age group is normally distributed with a standard deviation of 3 hours. We wish to compute the probability that the average number of hours of TV watched by 25 of these children will be greater than 26 hours. The area under the standard…A coin-operated drink machine was designed to discharge a mean of 8 fluid ounces of coffee per cup. In a test of the machine, the discharge amounts in 18 randomly chosen cups of coffee from the machine were recorded. The sample mean and sample standard deviation were 8.04 fluid ounces and 0.27 fluid ounces, respectively. If we assume that the discharge amounts are approximately normally distributed, is there enough evidence, to conclude that the population mean discharge, μ, differs from 8 fluid ounces? Use the 0.05 level of significance. Perform a two-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places. a. State the null hypothesis H0 and the alternative hypothesis H1. b. Find the value of the test statistic. Round to three or more decimal places. c. Find the p-value. Round to three or more decimal places. d. Can we conclude that the mean discharge differs from 8 fluid ounces?A consumer products company is formulating a new shampoo and is interested in foam height (in millimeters). Foam height is approximately normally distributed and has a standard deviation of 20 millimeters. The company wishes to test Ho: H = 175 millimeters versus H: u > 175 millimeters using the results of n 10 samples. %3D Identify the appropriate hypotheses tests O a. Test on Mean, Variance Known O b. Test on Population Proportion Oc. Test on Variance and Standard Deviation Od. Test on Mean, Variance Unknown
- A coin-operated drink machine was designed to discharge a mean of 7 fluid ounces of coffee per cup. In a test of the machine, the discharge amounts in 19 randomly chosen cups of coffee from the machine were recorded. The sample mean and sample standard deviation were 6.89 fluid ounces and 0.19fluid ounces, respectively.If we assume that the discharge amounts are approximately normally distributed, is there enough evidence, to conclude that the population mean discharge, μ, differs from 7 fluid ounces? Use the 0.05 level of significance. Perform a two-tailed test. Then complete the parts below.Carry your intermediate computations to three or more decimal places. a) State the null hypothesis H0 and the alternative hypothesis H1 . b) Find the value of the test statistic. (Round to three or more decimal places.) (c) Find the two critical values. (Round to three or more decimal places.) d. Can we conclude that the mean discharge differs from 7 fluid ounces?Residents of the town of Alternateville have recently complained of inconsistent shipping charges at their local Post Office. They believe the scales at the Post Office are too inconsistent, translating to unfair charges. The weight of a parcel is measured using an electronic scale that reports the true weight plus a random fluctuation (i.e., noise) which is normally distributed with a mean of zero, and independent of parcel weight. The company that manufactures the electronic scale claims that the standard deviation of the fluctuation is within 8 grams and that this fluctuation meets the industry standard. To test the manufacturer's claim, town officials measure the weight of the same package 4 times, recording the following weights (in grams): 95.6, 98.4, 104.6, and 95.1. At the a = 5% level, is there sufficient evidence to support the residents' claim? Specify the null and alternative hypotheses. O (a) Hoo8g, H₁ : 0 = 8g O (b) Ho≥ 8g, H₁:0< O (c) Hoo8g, H₁ 8g O (d) Hoo < 8g, o≥ 8g…A researcher compares two compounds (1 and 2) used in the manufacture of car tires that are designed to reduce braking distances for SUVS equipped with the tires. SUVS equipped with tires using compound 1 have a mean braking distance of 55 feet and a standard deviation of 14.0 feet. SUVS equipped with tires using compound 2 have a mean braking distance of 58 feet and a standard deviation of 13.7 feet. Suppose that a sample of 81 braking tests are performed for each compound. Using these results, test the claim that the braking distance for SUVS equipped with tires using compound 1 is shorter than the braking distance when compound 2 is used. Let u be the true mean braking distance corresponding to compound 1 and uz be the true mean braking distance corresponding to compound 2. Use the 0.05 level of significance. Step 1 of 4: State the null and alternative hypotheses for the test. 囲 Tables E Keypad Answer Keyboard Shortcuts Họ: 4 42 Submit Answer O 2020 Hawkes Learning 855 AM P Search…
- An agricultural company is trying to decide which type of fertilizer to use on its crops. The company concerned with the average yield on its crops as well as the variance of their yields. In a sample of 41 different fields with using fertilizer A, the average crop yield per acre is 184 tons with a standard deviation of 32 tons. In a separate sample of 41 different fields using fertilizer B, the average crop yield is 168 tons with a standard deviation of 26 tons. When testing the hypothesis (at the 1% level of significance) that the variance of one of these yields is significantly larger than the other, what is the test statistic? (please round your answer to 2 decimal places)Scores on a certain "IQ" test for 18-25 year olds are normally distributed. A researcher believes that the average IQ score for students at a certain NJ college is less than 110 points, and so wants to test this hypothesis. The researcher obtain a SRS of 55 student IQ scores from school records and found the mean of the 55 results was 107 with a sample standard deviation of 23. The level of significance (alpha) used for this problem is 0.05. Find/Calculate the P-value for this hypothesis test (show full calculator syntax) Stat Tests t tests , t test, 110, 107,23,55, , p = .156 Stat Tests t tests , t test, 110, 107,23,55, < ,р -.031 Stat Tests t tests , t test, 110, 107,23,55, = , p = .117Suppose there are two different vaccines for Covid, Vaccine X and Vaccine Y. An interesting question is which vaccine has a higher 6-month antibody effectiveness quotient (6AEQ). To examine this we randomly select 75 recipients of vaccine X and 83 recipients of vaccine Y. The vaccine X recipients had a mean 6AEQ of x = 129. The vaccine Y recipients had a mean 6AEQ of y = 133. It is recognized that the true standard deviation of 6AEQ for vaccine X recipients is a = 9.7 while it is recognized that the true standard deviation of 6AEQ for vaccine Y recipients is σy = 10.7. The true (unknown) mean 6AEQ for vaccine X recipients is x, while the true (unknown) mean 6AEQ for vaccine Y recipients is My. 6AEQ measurements are known to be a normally distributed. In summary: Type Sample Size Sample Mean Standard Deviation Vaccine X 75 129 Vaccine Y 83 133 9.7 10.7 a)Calculate the variance of the random variable X which is the mean of the 6AEQ measurements of the 75 vaccine X recipients. b)Calculate…
- The effects of an iron supplement in increasing hemoglobin levels is being clinically tested on a group of 160 patients suffering from anemia (low iron). Combined with a specific dietary plan, those using the supplement experienced an average hemoglobin increase of 6.8 g/dL. It is known from previous clinical trials that the standard deviation of the increase in hemoglobin levels as a result of using the supplement is 2.9 g/dL. Calculate the margin of error and construct the 99% confidence interval for the true mean hemoglobin-level increase caused by the supplement. 1. E= Round to 3 significant digits 2. ______ < μ <_____ g/dL Round to 2 decimal placesA coin-operated drink machine was designed to discharge a mean of 9 fluid ounces of coffee per cup. In a test of the machine, the discharge amounts in 15 randomly chosen cups of coffee from the machine were recorded. The sample mean and sample standard deviation were 9.13 fluid ounces and 0.22 fluid ounces, respectively. If we assume that the discharge amounts are approximately normally distributed, is there enough evidence, to conclude that the population mean discharge, μ, differs from 9 fluid ounces? Use the 0.10 level of significance. Perform a two-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places. (If necessary, consult a list of formulas.) (a) State the null hypothesis H and the alternative hypothesis H Ho : 0 H₁:0 (b) Determine the type of test statistic to use. (Choose one) ▼ (c) Find the value of the test statistic. (Round to three or more decimal places.) 0 (d) Find the p-value. (Round to three or more decimal…In a university it is generally said that the academic performance of the faculty A is lower than that of faculty B. The head of grades has been asked about the respective averages and standard deviations, and he only remembers the latter, 0.7 and 0.86 respectively. It is proposed to carry out a study with two samples of size 20 and 28 in each faculty, obtaining averages of 3.32 and 3.50. At the 5% level, can we accept what is generally said?
