A horizontal load PP is applied to an assembly consisting of two inclined bars, as shown in the figure. The cross-sectional area of bar (1) is 1.401.40 in.2in.2, and the cross-sectional area of bar (2) is 1.901.90 in.2in.2. The normal stress in either bar may not exceed 2121 ksiksi. Determine the maximum load PP that may be applied to this assembly. Assume dimensions of a=16.0a=16.0 ftft, b=6.5b=6.5 ftft, and c=14.0c=14.0 ftft. a) Determine the allowable force F1 in member (1) and the allowable force F2 in member (2). b) Find the angle θAB between member (1) and the horizontal direction, and also the angle θBC between member (2) and the horizontal direction c) Find the ratio, (F1/F2), where F1 is the force in member (1) and F2 is the force in member (2). Both bars are in tension, so these forces are both positive according to the sign conventions. d) Make an assumption for the maximum load case, referred to as “Load Case A”, in which the force in member (1) will control the capacity of the two-bar assembly. For this assumption, which may or may not be correct, the force in member (1) is F1,A=F1, allow. Enter the value of the force in member 2 for Load Case A. e) Make a new assumption for the maximum load case, referred to as “Load Case B”, in which the force in member (2) will control the capacity of the two-bar assembly. For this assumption, which may or may not be correct, the force in member (2) is F2,B=F2, allow. Enter the value of the force in member 1 for Load Case B. f) Enter the forces in the members corresponding to the correct maximum load case assumption, Load Case A or Load Case B. g) Determine the maximum load PP that may be applied to this assembly.
A horizontal load PP is applied to an assembly consisting of two inclined bars, as shown in the figure. The cross-sectional area of bar (1) is 1.401.40 in.2in.2, and the cross-sectional area of bar (2) is 1.901.90 in.2in.2. The normal stress in either bar may not exceed 2121 ksiksi. Determine the maximum load PP that may be applied to this assembly. Assume dimensions of a=16.0a=16.0 ftft, b=6.5b=6.5 ftft, and c=14.0c=14.0 ftft.
a) Determine the allowable force F1 in member (1) and the allowable force F2 in member (2).
b) Find the angle θAB between member (1) and the horizontal direction, and also the angle θBC between member (2) and the horizontal direction
c) Find the ratio, (F1/F2), where F1 is the force in member (1) and F2 is the force in member (2). Both bars are in tension, so these forces are both positive according to the sign conventions.
d) Make an assumption for the maximum load case, referred to as “Load Case A”, in which the force in member (1) will control the capacity of the two-bar assembly. For this assumption, which may or may not be correct, the force in member (1) is F1,A=F1, allow. Enter the value of the force in member 2 for Load Case A.
e) Make a new assumption for the maximum load case, referred to as “Load Case B”, in which the force in member (2) will control the capacity of the two-bar assembly. For this assumption, which may or may not be correct, the force in member (2) is F2,B=F2, allow. Enter the value of the force in member 1 for Load Case B.
f) Enter the forces in the members corresponding to the correct maximum load case assumption, Load Case A or Load Case B.
g) Determine the maximum load PP that may be applied to this assembly.
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