A flocculator is 16 ft (4.88 m) deep, 40 ft (12.2 m) wide, and 80 ft (24.4 m) long. The flow of the water plant is 13 mgd (20 cfs, 0,57 m3 /s). Rotating paddles are supported parallel to four horizontal shafts. The rotating speed is 2.0 rpm. The center line of the paddles is 5.5 ft (1.68 m) from the shaft (mid-depth of the basin). Each shaft equipped with six paddles. Each paddle blade is 10 in (25 cm) wide and 38 ft (11.6) long. Assume the mean velocity of the water is 28 percent of the velocity of the paddles and their drag coefficient is 1.9. 55 p.
A flocculator is 16 ft (4.88 m) deep, 40 ft (12.2 m) wide, and 80 ft (24.4 m) long. The flow of
the water plant is 13 mgd (20 cfs, 0,57 m3
/s).
Rotating paddles are supported parallel to four horizontal shafts. The rotating speed is 2.0
rpm. The center line of the paddles is 5.5 ft (1.68 m) from the shaft (mid-depth of the basin).
Each shaft equipped with six paddles. Each paddle blade is 10 in (25 cm) wide and 38 ft (11.6)
long. Assume the mean velocity of the water is 28 percent of the velocity of the paddles and
their drag coefficient is 1.9.
55 p.
Estimate:
(a) the difference in velocity between the paddles and water
(b) the useful power input
(c) the energy consumption per million gallons (Mgal)
(d) the detention time
(e) the value of G and Gt at 60 o
F
(f) the loading rate of the flocculator
• Find velocity differential v
• Find P
• Determine energy consumption E
• Determine detention time t
• Compute G and Gt
• Compute the loading rate
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