A flocculator is 16 ft (4.88 m) deep, 40 ft (12.2 m) wide, and 80 ft (24.4 m) long. The flow of the water plant is 13 mgd (20 cfs, 0.566 m³/s). Rotating paddles are supported parallel to four horizontal shafts. The rotating speed is 2 rpm. The centre line of the paddles is 5.5 ft (1.68 m) from the shaft (mid-depth of the basin). Each shaft equipped with six paddles. Each paddle blade is 10 in (25 cm) wide and 38 ft (11.6m) long. Assume the mean velocity of the water is 28 percent of the velocity of the paddles and their drag coefficient is 1.9. Estimate: (a) the difference in velocity between the paddles and water (b) the useful power input (c) the energy consumption per million gallons (Mgal) (d) the detention time (e) the value of G and Gr at 60 °F (f) the loading rate of the flocculator
A flocculator is 16 ft (4.88 m) deep, 40 ft (12.2 m) wide, and 80 ft (24.4 m) long. The flow of the water plant is 13 mgd (20 cfs, 0.566 m³/s). Rotating paddles are supported parallel to four horizontal shafts. The rotating speed is 2 rpm. The centre line of the paddles is 5.5 ft (1.68 m) from the shaft (mid-depth of the basin). Each shaft equipped with six paddles. Each paddle blade is 10 in (25 cm) wide and 38 ft (11.6m) long. Assume the mean velocity of the water is 28 percent of the velocity of the paddles and their drag coefficient is 1.9. Estimate: (a) the difference in velocity between the paddles and water (b) the useful power input (c) the energy consumption per million gallons (Mgal) (d) the detention time (e) the value of G and Gr at 60 °F (f) the loading rate of the flocculator
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
![A flocculator is 16 ft (4.88 m) deep, 40 ft (12.2 m) wide, and 80 ft (24.4 m)
long. The flow of the water plant is 13 mgd (20 cfs, 0.566 m³/s). Rotating paddles are
supported parallel to four horizontal shafts. The rotating speed is 2 rpm. The centre line
of the paddles is 5.5 ft (1.68 m) from the shaft (mid-depth of the basin). Each shaft
equipped with six paddles. Each paddle blade is 10 in (25 cm) wide and 38 ft (11.6m)
long. Assume the mean velocity of the water is 28 percent of the velocity of the paddles
and their drag coefficient is 1.9. Estimate:
(a) the difference in velocity between the paddles and water
(b) the useful power input
(c) the energy consumption per million gallons (Mgal)
(d) the detention time
(e) the value of G and Gr at 60 °F
(f) the loading rate of the flocculator](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1aa5ff01-58a5-4f17-87cd-234e60ad4800%2Fd14b9c95-f6a5-49b8-9cfd-3c5965e904d2%2Fqjg06k7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A flocculator is 16 ft (4.88 m) deep, 40 ft (12.2 m) wide, and 80 ft (24.4 m)
long. The flow of the water plant is 13 mgd (20 cfs, 0.566 m³/s). Rotating paddles are
supported parallel to four horizontal shafts. The rotating speed is 2 rpm. The centre line
of the paddles is 5.5 ft (1.68 m) from the shaft (mid-depth of the basin). Each shaft
equipped with six paddles. Each paddle blade is 10 in (25 cm) wide and 38 ft (11.6m)
long. Assume the mean velocity of the water is 28 percent of the velocity of the paddles
and their drag coefficient is 1.9. Estimate:
(a) the difference in velocity between the paddles and water
(b) the useful power input
(c) the energy consumption per million gallons (Mgal)
(d) the detention time
(e) the value of G and Gr at 60 °F
(f) the loading rate of the flocculator
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