A family consisting of three people—P1 , P2, and P3—belongs to a medical clinic that always has a physician at each of stations 1, 2, and 3. During a certain week, each member of the family visits the clinic exactly once and is randomly assigned to a station. One experimental outcome is (1, 2, 1), which means that P1 is assigned to station 1, P2 to station 2, and P3 to station 1. Using the outcomes for the chance experiment, identify outcomes in each of the following events. Let A be the event that all three people go to the same station, B be the event that all three people go to different stations, and C be the event that no one goes to station 3. (a) BC BC = {(1, 1, 1), (1, 1, 2), (1, 1, 3), (1, 2, 1), (1, 2, 2), (1, 3, 1), (1, 3, 3), (2, 1, 1), (2, 1, 2), (2, 2, 1),(2, 2, 2), (2, 2, 3), (2, 3, 2), (2, 3, 3), (3, 1, 1), (3, 1, 3), (3, 2, 2), (3, 2, 3), (3, 3, 1), (3, 3, 2),(3, 3, 3)}BC = {(1, 1, 1), (1, 1, 2), (1, 1, 3), (1, 2, 1), (1, 2, 2), (1, 3, 1), (1, 3, 2), (1, 3, 3), (2, 1, 1), (2, 1, 2),(2, 2, 1), (2, 2, 2), (2, 3, 2), (2, 3, 3), (3, 1, 1), (3, 1, 2), (3, 1, 3), (3, 2, 2), (3, 2, 3), (3, 3, 1), (3, 3, 2),(3, 3, 3)}     BC = {(1, 1, 1), (1, 1, 2), (1, 1, 3), (1, 2, 1), (1, 2, 2), (1, 3, 1), (1, 3, 2), (1, 3, 3), (2, 1, 1), (2, 1, 3),(2, 2, 1), (2, 2, 2), (2, 2, 3), (2, 3, 1), (2, 3, 2), (2, 3, 3), (3, 1, 3), (3, 2, 1), (3, 2, 2), (3, 2, 3), (3, 3, 1),(3, 3, 2), (3, 3, 3)}BC = {(1, 1, 1), (1, 1, 2), (1, 1, 3), (1, 2, 1), (1, 2, 2), (1, 3, 1), (1, 3, 3), (2, 1, 1), (2, 1, 2), (2, 1, 3),(2, 2, 1), (2, 2, 2), (2, 2, 3), (2, 3, 1), (2, 3, 2), (2, 3, 3), (3, 1, 1), (3, 1, 2), (3, 1, 3), (3, 2, 1), (3, 2, 2),(3, 2, 3), (3, 3, 3)}BC = {(1, 1, 1), (1, 1, 3), (1, 2, 1), (1, 2, 2), (1, 3, 1), (1, 3, 3), (2, 1, 1), (2, 1, 2), (2, 2, 1), (2, 2, 2),(2, 2, 3), (2, 3, 3), (3, 1, 1), (3, 1, 2), (3, 1, 3), (3, 2, 2), (3, 2, 3), (3, 3, 1), (3, 3, 2), (3, 3, 3)} (b) CC CC = {(1, 1, 1), (1, 1, 2), (1, 1, 3), (1, 2, 1), (1, 2, 2), (1, 2, 3), (1, 3, 1), (1, 3, 2), (1, 3, 3), (2, 1, 1),(2, 1, 2), (2, 1, 3), (2, 2, 1), (2, 3, 1), (3, 1, 1), (3, 1, 2), (3, 1, 3), (3, 2, 1), (3, 3, 1)}CC = {(1, 1, 2), (1, 2, 1), (1, 2, 2), (1, 2, 3), (1, 3, 2), (2, 1, 1), (2, 1, 2), (2, 1, 3), (2, 2, 1), (2, 2, 2),(2, 2, 3), (2, 3, 1), (2, 3, 2), (2, 3, 3), (3, 1, 2), (3, 2, 1), (3, 2, 2), (3, 2, 3), (3, 3, 2)}     CC = {(1, 1, 3), (1, 2, 3), (1, 3, 1), (1, 3, 2), (1, 3, 3), (2, 1, 3), (2, 2, 3), (2, 3, 1), (2, 3, 2), (2, 3, 3),(3, 1, 1), (3, 1, 2), (3, 1, 3), (3, 2, 1), (3, 2, 2), (3, 2, 3), (3, 3, 1), (3, 3, 2), (3, 3, 3)}CC = {(1, 1, 3), (1, 2, 3), (1, 3, 1), (1, 3, 2), (1, 3, 3), (2, 1, 3), (2, 2, 3),(2, 3, 2), (2, 3, 3), (3, 1, 1),(3, 1, 2), (3, 1, 3), (3, 2, 1), (3, 2, 2), (3, 2, 3), (3, 3, 1), (3, 3, 2), (3, 3, 3)}CC = {(1, 1, 2), (1, 2, 1), (1, 2, 2), (1, 2, 3), (1, 3, 2), (2, 1, 1), (2, 1, 2), (2, 1, 3), (2, 2, 1), (2, 2, 2),(2, 2, 3), (2, 3, 1), (2, 3, 2), (3, 1, 2), (3, 2, 1), (3, 2, 2), (3, 2, 3), (3, 3, 2)} (c) A ∪ B A ∪ B = {(1, 1, 1), (2, 2, 2), (3, 3, 3), (1, 2, 3), (2, 3, 1), (3, 1, 2), (1, 3, 2), (2, 1, 3), (3, 2, 1)}A ∪ B = {(1, 1, 1), (1, 1, 2), (1, 1, 3), (2, 2, 1), (2, 2, 2), (2, 2, 3), (3, 3, 1), (3, 3, 2), (3, 3, 3), (1, 2, 3),(2, 3, 1), (3, 1, 2), (1, 3, 2), (2, 1, 3), (3, 2, 1)}     A ∪ B = {(1, 1, 1), (2, 2, 2), (3, 3, 3), (1, 2, 3), (2, 3, 1), (3, 1, 2), (1, 3, 2), (3, 2, 1)}A ∪ B = {(1, 1, 1), (1, 1, 2), (1, 1, 3), (2, 1, 1), (2, 2, 2), (2, 2, 3), (3, 3, 1), (3, 3, 2), (3, 3, 3), (1, 2, 3),(2, 3, 1), (3, 1, 2), (1, 2, 3), (2, 1, 3), (3, 2, 1)}A ∪ B = the empty set (d) A ∩ B A ∩ B = the empty setA ∩ B = {(1, 1, 1), (2, 2, 2), (3, 3, 3), (1, 2, 3), (2, 3, 1), (3, 1, 2), (1, 3, 2), (2, 1, 3), (3, 2, 1)}     A ∩ B = {(1, 1, 1), (1, 1, 2), (1, 1, 3), (2, 2, 1), (2, 2, 2), (2, 2, 3), (3, 3, 1), (3, 3, 2), (3, 3, 3), (1, 2, 3),(2, 3, 1), (3, 1, 2), (1, 3, 2), (2, 1, 3), (3, 2, 1)}A ∩ B = {(1, 1, 1), (2, 2, 2), (3, 3, 3), (1, 2, 3), (2, 3, 1), (3, 1, 2), (1, 3, 2), (3, 2, 1)}A ∩ B = {(1, 1, 1), (1, 1, 2), (1, 1, 3), (2, 1, 1), (2, 2, 2), (2, 2, 3), (3, 3, 1), (3, 3, 2), (3, 3, 3), (1, 2, 3),(2, 3, 1), (3, 1, 2), (1, 2, 3), (2, 1, 3), (3, 2, 1)} (e) A ∩ C A ∩ C = {(2, 2, 2), (3, 3, 3)}A ∩ C = {(1, 1, 1), (3, 3, 3)}     A ∩ C = {(1, 1, 1), (2, 2, 2)}A ∩ C = {(2, 2, 2), (2, 2, 3), (3, 3, 2), (3, 3, 3)}A ∩ C = {(1, 1, 1), (1, 1, 3), (3, 3, 1), (3, 3, 3)}A ∩ C = {(1, 1, 1), (1, 1, 2), (2, 2, 1), (2, 2, 2)}

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
icon
Related questions
Question
A family consisting of three people—P1 , P2, and P3—belongs to a medical clinic that always has a physician at each of stations 1, 2, and 3. During a certain week, each member of the family visits the clinic exactly once and is randomly assigned to a station. One experimental outcome is (1, 2, 1), which means that P1 is assigned to station 1, P2 to station 2, and P3 to station 1.
Using the outcomes for the chance experiment, identify outcomes in each of the following events. Let A be the event that all three people go to the same station, B be the event that all three people go to different stations, and C be the event that no one goes to station 3.
(a)
BC
BC = {(1, 1, 1), (1, 1, 2), (1, 1, 3), (1, 2, 1), (1, 2, 2), (1, 3, 1), (1, 3, 3), (2, 1, 1), (2, 1, 2), (2, 2, 1),(2, 2, 2), (2, 2, 3), (2, 3, 2), (2, 3, 3), (3, 1, 1), (3, 1, 3), (3, 2, 2), (3, 2, 3), (3, 3, 1), (3, 3, 2),(3, 3, 3)}BC = {(1, 1, 1), (1, 1, 2), (1, 1, 3), (1, 2, 1), (1, 2, 2), (1, 3, 1), (1, 3, 2), (1, 3, 3), (2, 1, 1), (2, 1, 2),(2, 2, 1), (2, 2, 2), (2, 3, 2), (2, 3, 3), (3, 1, 1), (3, 1, 2), (3, 1, 3), (3, 2, 2), (3, 2, 3), (3, 3, 1), (3, 3, 2),(3, 3, 3)}     BC = {(1, 1, 1), (1, 1, 2), (1, 1, 3), (1, 2, 1), (1, 2, 2), (1, 3, 1), (1, 3, 2), (1, 3, 3), (2, 1, 1), (2, 1, 3),(2, 2, 1), (2, 2, 2), (2, 2, 3), (2, 3, 1), (2, 3, 2), (2, 3, 3), (3, 1, 3), (3, 2, 1), (3, 2, 2), (3, 2, 3), (3, 3, 1),(3, 3, 2), (3, 3, 3)}BC = {(1, 1, 1), (1, 1, 2), (1, 1, 3), (1, 2, 1), (1, 2, 2), (1, 3, 1), (1, 3, 3), (2, 1, 1), (2, 1, 2), (2, 1, 3),(2, 2, 1), (2, 2, 2), (2, 2, 3), (2, 3, 1), (2, 3, 2), (2, 3, 3), (3, 1, 1), (3, 1, 2), (3, 1, 3), (3, 2, 1), (3, 2, 2),(3, 2, 3), (3, 3, 3)}BC = {(1, 1, 1), (1, 1, 3), (1, 2, 1), (1, 2, 2), (1, 3, 1), (1, 3, 3), (2, 1, 1), (2, 1, 2), (2, 2, 1), (2, 2, 2),(2, 2, 3), (2, 3, 3), (3, 1, 1), (3, 1, 2), (3, 1, 3), (3, 2, 2), (3, 2, 3), (3, 3, 1), (3, 3, 2), (3, 3, 3)}
(b)
CC
CC = {(1, 1, 1), (1, 1, 2), (1, 1, 3), (1, 2, 1), (1, 2, 2), (1, 2, 3), (1, 3, 1), (1, 3, 2), (1, 3, 3), (2, 1, 1),(2, 1, 2), (2, 1, 3), (2, 2, 1), (2, 3, 1), (3, 1, 1), (3, 1, 2), (3, 1, 3), (3, 2, 1), (3, 3, 1)}CC = {(1, 1, 2), (1, 2, 1), (1, 2, 2), (1, 2, 3), (1, 3, 2), (2, 1, 1), (2, 1, 2), (2, 1, 3), (2, 2, 1), (2, 2, 2),(2, 2, 3), (2, 3, 1), (2, 3, 2), (2, 3, 3), (3, 1, 2), (3, 2, 1), (3, 2, 2), (3, 2, 3), (3, 3, 2)}     CC = {(1, 1, 3), (1, 2, 3), (1, 3, 1), (1, 3, 2), (1, 3, 3), (2, 1, 3), (2, 2, 3), (2, 3, 1), (2, 3, 2), (2, 3, 3),(3, 1, 1), (3, 1, 2), (3, 1, 3), (3, 2, 1), (3, 2, 2), (3, 2, 3), (3, 3, 1), (3, 3, 2), (3, 3, 3)}CC = {(1, 1, 3), (1, 2, 3), (1, 3, 1), (1, 3, 2), (1, 3, 3), (2, 1, 3), (2, 2, 3),(2, 3, 2), (2, 3, 3), (3, 1, 1),(3, 1, 2), (3, 1, 3), (3, 2, 1), (3, 2, 2), (3, 2, 3), (3, 3, 1), (3, 3, 2), (3, 3, 3)}CC = {(1, 1, 2), (1, 2, 1), (1, 2, 2), (1, 2, 3), (1, 3, 2), (2, 1, 1), (2, 1, 2), (2, 1, 3), (2, 2, 1), (2, 2, 2),(2, 2, 3), (2, 3, 1), (2, 3, 2), (3, 1, 2), (3, 2, 1), (3, 2, 2), (3, 2, 3), (3, 3, 2)}
(c)
A ∪ B
AB = {(1, 1, 1), (2, 2, 2), (3, 3, 3), (1, 2, 3), (2, 3, 1), (3, 1, 2), (1, 3, 2), (2, 1, 3), (3, 2, 1)}AB = {(1, 1, 1), (1, 1, 2), (1, 1, 3), (2, 2, 1), (2, 2, 2), (2, 2, 3), (3, 3, 1), (3, 3, 2), (3, 3, 3), (1, 2, 3),(2, 3, 1), (3, 1, 2), (1, 3, 2), (2, 1, 3), (3, 2, 1)}     AB = {(1, 1, 1), (2, 2, 2), (3, 3, 3), (1, 2, 3), (2, 3, 1), (3, 1, 2), (1, 3, 2), (3, 2, 1)}AB = {(1, 1, 1), (1, 1, 2), (1, 1, 3), (2, 1, 1), (2, 2, 2), (2, 2, 3), (3, 3, 1), (3, 3, 2), (3, 3, 3), (1, 2, 3),(2, 3, 1), (3, 1, 2), (1, 2, 3), (2, 1, 3), (3, 2, 1)}AB = the empty set
(d)
A ∩ B
AB = the empty setAB = {(1, 1, 1), (2, 2, 2), (3, 3, 3), (1, 2, 3), (2, 3, 1), (3, 1, 2), (1, 3, 2), (2, 1, 3), (3, 2, 1)}     AB = {(1, 1, 1), (1, 1, 2), (1, 1, 3), (2, 2, 1), (2, 2, 2), (2, 2, 3), (3, 3, 1), (3, 3, 2), (3, 3, 3), (1, 2, 3),(2, 3, 1), (3, 1, 2), (1, 3, 2), (2, 1, 3), (3, 2, 1)}AB = {(1, 1, 1), (2, 2, 2), (3, 3, 3), (1, 2, 3), (2, 3, 1), (3, 1, 2), (1, 3, 2), (3, 2, 1)}AB = {(1, 1, 1), (1, 1, 2), (1, 1, 3), (2, 1, 1), (2, 2, 2), (2, 2, 3), (3, 3, 1), (3, 3, 2), (3, 3, 3), (1, 2, 3),(2, 3, 1), (3, 1, 2), (1, 2, 3), (2, 1, 3), (3, 2, 1)}
(e)
A ∩ C
AC = {(2, 2, 2), (3, 3, 3)}AC = {(1, 1, 1), (3, 3, 3)}     AC = {(1, 1, 1), (2, 2, 2)}AC = {(2, 2, 2), (2, 2, 3), (3, 3, 2), (3, 3, 3)}AC = {(1, 1, 1), (1, 1, 3), (3, 3, 1), (3, 3, 3)}AC = {(1, 1, 1), (1, 1, 2), (2, 2, 1), (2, 2, 2)}
Expert Solution
Step 1

Hi! Thank you for the question. As per the honor code, we are allowed to answer three sub-parts at a time so we are answering the first three as you have not mentioned which of these you are looking for. Please re-submit the question separately for the remaining sub-parts.

It is given that:

A be the event that all the three people go to the same station.

B be the event that all the three people go to different stations.

and, C be the event that no one goes to the station 3.

and 1,2,1 denotes that the person 1 is assigned to the station 1 , person 2 to the station 2 and person 3 to the station 1.

trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps

Blurred answer
Similar questions
Recommended textbooks for you
MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
Statistics
ISBN:
9781119256830
Author:
Amos Gilat
Publisher:
John Wiley & Sons Inc
Probability and Statistics for Engineering and th…
Probability and Statistics for Engineering and th…
Statistics
ISBN:
9781305251809
Author:
Jay L. Devore
Publisher:
Cengage Learning
Statistics for The Behavioral Sciences (MindTap C…
Statistics for The Behavioral Sciences (MindTap C…
Statistics
ISBN:
9781305504912
Author:
Frederick J Gravetter, Larry B. Wallnau
Publisher:
Cengage Learning
Elementary Statistics: Picturing the World (7th E…
Elementary Statistics: Picturing the World (7th E…
Statistics
ISBN:
9780134683416
Author:
Ron Larson, Betsy Farber
Publisher:
PEARSON
The Basic Practice of Statistics
The Basic Practice of Statistics
Statistics
ISBN:
9781319042578
Author:
David S. Moore, William I. Notz, Michael A. Fligner
Publisher:
W. H. Freeman
Introduction to the Practice of Statistics
Introduction to the Practice of Statistics
Statistics
ISBN:
9781319013387
Author:
David S. Moore, George P. McCabe, Bruce A. Craig
Publisher:
W. H. Freeman