that 34 of the volunteers did not have any colds where 15 of them were in the 500 mg group, 11 of them were in the 1000 mg group, and the rest took no Vitamin C. Test the appropriate hypothesis at a = 0.10. Round your answers to three decimal places, if necessary. Fill in the hypotheses below: Ho: There is not C taken. Ha: There is C taken. Complete the table of expected counts under the null hypothesis: No Vitamin C 500mg Vitamin C ✓✓an association between the incidence of colds and the amount of vitamin an association between the incidence of colds and the amount of vitamin 1000mg Vitamin C At least one cold 32.938 17.438 11.625 No colds What is the critical value for this test? 4.605 18.063 9.563 11.625 Using your answer from the previous question, find the p-value. ▼ Part 2 of 5 Part 3 of 5 Part 4 of 5

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Chapter1: Starting With Matlab
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A researcher investigates whether there is an association between the incidence of colds and the amount of Vitamin C taken. The study involves 96 volunteers divided into three groups: 27 take 500 mg of Vitamin C, 18 take 1000 mg, and the remainder take no Vitamin C. By the end of the study, it is found that 34 volunteers did not experience any colds, with the distribution as follows: 15 in the 500 mg group, 11 in the 1000 mg group, and the rest with no Vitamin C.

### Hypothesis Testing

**Null Hypothesis (H₀):** There is not an association between the incidence of colds and the amount of Vitamin C taken.

**Alternative Hypothesis (Hₐ):** There is an association between the incidence of colds and the amount of Vitamin C taken.

### Expected Counts Table

To test the hypothesis, a table of expected counts under the null hypothesis is completed:

|                      | At least one cold | No colds   |
|----------------------|-------------------|------------|
| **No Vitamin C**     | 32.938            | 18.063     |
| **500mg Vitamin C**  | 17.438            | 9.563      |
| **1000mg Vitamin C** | 11.625            | 11.625     |

### Statistical Testing

The critical value for this test at a significance level of α = 0.10 is 4.605. 

To proceed, find the p-value using these expected counts, and compare it to the critical value to determine if the null hypothesis can be rejected. 

This setup is useful for illustrating the process of hypothesis testing and expected counts calculation in a categorical study context.
Transcribed Image Text:A researcher investigates whether there is an association between the incidence of colds and the amount of Vitamin C taken. The study involves 96 volunteers divided into three groups: 27 take 500 mg of Vitamin C, 18 take 1000 mg, and the remainder take no Vitamin C. By the end of the study, it is found that 34 volunteers did not experience any colds, with the distribution as follows: 15 in the 500 mg group, 11 in the 1000 mg group, and the rest with no Vitamin C. ### Hypothesis Testing **Null Hypothesis (H₀):** There is not an association between the incidence of colds and the amount of Vitamin C taken. **Alternative Hypothesis (Hₐ):** There is an association between the incidence of colds and the amount of Vitamin C taken. ### Expected Counts Table To test the hypothesis, a table of expected counts under the null hypothesis is completed: | | At least one cold | No colds | |----------------------|-------------------|------------| | **No Vitamin C** | 32.938 | 18.063 | | **500mg Vitamin C** | 17.438 | 9.563 | | **1000mg Vitamin C** | 11.625 | 11.625 | ### Statistical Testing The critical value for this test at a significance level of α = 0.10 is 4.605. To proceed, find the p-value using these expected counts, and compare it to the critical value to determine if the null hypothesis can be rejected. This setup is useful for illustrating the process of hypothesis testing and expected counts calculation in a categorical study context.
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