A culture is incubated for 10 hours. 1 hours after inoculation it reached the exponential growth phase. At this time point the cell density was 1x10^4 cells/ml. 5 hours after inoculation (still during the exponential growth phase) the cell density was 1x10^7 cells. Calculate K and g(t). The growth constant (k) is 1 minute. (round to 3 decimal points) The generation time (gt) is minutes. (round to whole number)

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A culture is incubated for 10 hours.
1 hours after inoculation it reached
the exponential growth phase. At
this time point the cell density was
1x10^4 cells/ml. 5 hours after
inoculation (still during the
exponential growth phase) the cell
density was 1x10^7 cells. Calculate
K and g(t).
The growth constant (k) is
minute. (round to 3 decimal points)
The generation time (gt) is
minutes. (round to whole number)
Transcribed Image Text:A culture is incubated for 10 hours. 1 hours after inoculation it reached the exponential growth phase. At this time point the cell density was 1x10^4 cells/ml. 5 hours after inoculation (still during the exponential growth phase) the cell density was 1x10^7 cells. Calculate K and g(t). The growth constant (k) is minute. (round to 3 decimal points) The generation time (gt) is minutes. (round to whole number)
I have diluted my culture 9x10^(-5)
times. What was the volume of the
stock and the volume of the media
for dilution 3 if the total volume of
each sub-dilution was 10 ml? Round
to 2 decimal places; do not write in
scientific notation.
PS: I may not have followed the
laboratorial principle of using at
least 100μl of stock for each
dilution (In truth: the numbers are
produced by a random number
generator).
Dilution 1: v(stock) = 0.2 ml,
v(media) = 9.8 ml
Dilution 2: v(d1) = 0.1 ml, v(media) =
9.9 ml
Dilution 3: v(d2) =
v(media) =
ml,
3
Transcribed Image Text:I have diluted my culture 9x10^(-5) times. What was the volume of the stock and the volume of the media for dilution 3 if the total volume of each sub-dilution was 10 ml? Round to 2 decimal places; do not write in scientific notation. PS: I may not have followed the laboratorial principle of using at least 100μl of stock for each dilution (In truth: the numbers are produced by a random number generator). Dilution 1: v(stock) = 0.2 ml, v(media) = 9.8 ml Dilution 2: v(d1) = 0.1 ml, v(media) = 9.9 ml Dilution 3: v(d2) = v(media) = ml, 3
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