A copper tube 55 mm in outside diameter and of wall thickness 5 mm fits loosely over a solid steel circular bar 40 mm in diameter. The two members are fastened together by two metal pins each 8 mm in diameter and passing transversely through both members, one pin being near each end of the assembly. At room temperature the assembly is just stress free when the pins are in position. The temperature of the entire assembly is then raised 40°C. Calculate the average shear stress in the pins. For copper E = 90 GPa, a = 18 × 10°/°C; for steel E 200 GPa, a = 12 x 106/°C. Ans. t = 132 MPa
A copper tube 55 mm in outside diameter and of wall thickness 5 mm fits loosely over a solid steel circular bar 40 mm in diameter. The two members are fastened together by two metal pins each 8 mm in diameter and passing transversely through both members, one pin being near each end of the assembly. At room temperature the assembly is just stress free when the pins are in position. The temperature of the entire assembly is then raised 40°C. Calculate the average shear stress in the pins. For copper E = 90 GPa, a = 18 × 10°/°C; for steel E 200 GPa, a = 12 x 106/°C. Ans. t = 132 MPa
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:A copper tube 55 mm in outside diameter and of wall thickness 5 mm fits loosely over a solid steel circular bar 40 mm in diameter. The
two members are fastened together by two metal pins each 8 mm in diameter and passing transversely through both members, one pin
being near each end of the assembly. At room temperature the assembly is just stress free when the pins are in position. The temperature
of the entire assembly is then raised 40°C. Calculate the average shear stress in the pins. For copper E = 90 GPa, a = 18 × 10°/°C;
for steel E 200 GPa, a = 12 x 106/°C. Ans. t = 132 MPa
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