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A biologist is examining two genetic mutations. Genetic mutation A occurs in 15% of the population, mutation B occurs in 4% of the population, and 1% of the population have mutation B and do not have mutation A. a) Is having mutation A independent of having mutation B? Explain/show the reasoning for your answer. b) Is not having mutation A independent of having mutation B?

A biologist is examining two genetic mutations. Genetic mutation A occurs in 15% of the population, mutation B occurs in 4% of the population, and 1% of the population have mutation B and do not have mutation A. a) Is having mutation A independent of having mutation B? Explain/show the reasoning for your answer. b) Is not having mutation A independent of having mutation B?

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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A biologist is examining two genetic mutations. Genetic mutation A occurs in 15% of the population, mutation B occurs in 4% of the population, and 1% of the population have mutation B and do not have mutation A. a) Is having mutation A independent of having mutation B? Explain/show the reasoning for your answer. b) Is not having mutation A independent of having mutation B? Explain/show the reasoning for your work.
Expert Solution
Step 1

Define the events,

A : mutation A occurs

B : mutation B occurs

Given, Genetic mutation A occurs in 15% of the population, mutation B occurs 4% of the population. 

So, P(A) = 0.15, P(B) = 0.04

1% of the population have mutation B and do not have mutation A.

So, P(Ac∩B) = 0.01

Now, P(B) = P(A∩B)+P(Ac∩B) 

Hence, P(A∩B) = P(B) - P(Ac∩B) = 0.04-0.01 = 0.03

P(Ac) = 1- P(A) = 1-0.15 = 0.85

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