The governor of the state of Maryland, Martin O'Malley, ran for re-election in November, 2010. Before the election, from September 22-26, 2010, the Washington Post conducted a poll in which respondents were asked: "lf the election for Maryland governor were held today, for whom would you vote?" In an article summarizing the results of the poll, Washington Post journalists reported that "A total of 1,448 randomly selected adults in Maryland were interviewed, including... 730 voters likely to cast ballots." The sample was intended to represent the population of likely Maryland voters at that time period in September, 2010. The article summarized the responses of the likely voters using the following categories: "for Governor Martin O'Malley", "for Bob Ehrlich", and "for Other/no opinion".

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### Analysis of 2010 Maryland Gubernatorial Poll Results

#### Poll Overview
Before the 2010 gubernatorial election in Maryland, a poll was conducted from September 22–26 by the Washington Post. The poll sampled voters to determine their preference if the governor election were held at that time.

#### Methodology
- **Sample Size:** 1,448 randomly selected adults in Maryland.
  - **Likely Voters:** Out of the total sample, 730 were identified as likely voters.

Respondents were asked, “If the election for Maryland governor were held today, for whom would you vote?” The poll provided three response categories:
1. For Governor Martin O'Malley
2. For Bob Ehrlich
3. For Other/No opinion

#### Poll Results
The following is a likely tally of the responses from the 730 likely voters:
- **For Governor Martin O'Malley:** 382 responses
- **For Bob Ehrlich:** 302 responses
- **For Other/No opinion:** 46 responses

#### Statistical Analysis
To verify if there is a significant difference in the distribution of voter preferences as compared to previous polling data, a Chi-square goodness-of-fit test was performed. Previous polls suggested the following expected distributions:
- **O'Malley:** 48%
- **Ehrlich:** 46%
- **Other/No opinion:** 6%

#### Calculation Summary
1. **Observed Frequencies:**
   - **O'Malley:** 382
   - **Ehrlich:** 302
   - **Other/No opinion:** 46

2. **Expected Frequencies (based on earlier percentage data):**
   - **O'Malley:** 730 × 0.48 = 350.4
   - **Ehrlich:** 730 × 0.46 = 335.8
   - **Other/No opinion:** 730 × 0.06 = 43.8

3. **Chi-square Calculation:**
   \[ χ^2 = \sum \frac{{(O - E)^2}}{E} \]
   - O'Malley: \[ \frac{{(382 - 350.4)^2}}{350.4} = 2.850 \]
   - Ehrlich: \[ \frac{{(302 - 335.8)^2}}{335.8} = 3.
Transcribed Image Text:### Analysis of 2010 Maryland Gubernatorial Poll Results #### Poll Overview Before the 2010 gubernatorial election in Maryland, a poll was conducted from September 22–26 by the Washington Post. The poll sampled voters to determine their preference if the governor election were held at that time. #### Methodology - **Sample Size:** 1,448 randomly selected adults in Maryland. - **Likely Voters:** Out of the total sample, 730 were identified as likely voters. Respondents were asked, “If the election for Maryland governor were held today, for whom would you vote?” The poll provided three response categories: 1. For Governor Martin O'Malley 2. For Bob Ehrlich 3. For Other/No opinion #### Poll Results The following is a likely tally of the responses from the 730 likely voters: - **For Governor Martin O'Malley:** 382 responses - **For Bob Ehrlich:** 302 responses - **For Other/No opinion:** 46 responses #### Statistical Analysis To verify if there is a significant difference in the distribution of voter preferences as compared to previous polling data, a Chi-square goodness-of-fit test was performed. Previous polls suggested the following expected distributions: - **O'Malley:** 48% - **Ehrlich:** 46% - **Other/No opinion:** 6% #### Calculation Summary 1. **Observed Frequencies:** - **O'Malley:** 382 - **Ehrlich:** 302 - **Other/No opinion:** 46 2. **Expected Frequencies (based on earlier percentage data):** - **O'Malley:** 730 × 0.48 = 350.4 - **Ehrlich:** 730 × 0.46 = 335.8 - **Other/No opinion:** 730 × 0.06 = 43.8 3. **Chi-square Calculation:** \[ χ^2 = \sum \frac{{(O - E)^2}}{E} \] - O'Malley: \[ \frac{{(382 - 350.4)^2}}{350.4} = 2.850 \] - Ehrlich: \[ \frac{{(302 - 335.8)^2}}{335.8} = 3.
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