A 6.22 kg particle with velocity v = (9.72 m/s)î – (8.99 m/s)ĵ is at x = 2.96 m, y = 5.29 m. It is pulled by a 5.05 N force in the negative x direction. About the origin, what are (a) the particle's angular momentum, (b) the torque acting on the particle, and (c) the rate at which the angular momentum is changing? (a) Number i k Units (b) Number i k Units (c) Number i k Units

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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A 6.22 kg particle with velocity v = (9.72 m/s)î – (8.99 m/s)j is at x = 2.96 m, y = 5.29 m. It is pulled by a 5.05 N force in the
negative x direction. About the origin, what are (a) the particle's angular momentum, (b) the torque acting on the particle, and (c) the
rate at which the angular momentum is changing?
(a) Number
i
k Units
(b) Number
i
k Units
(c) Number
i
k Units
Transcribed Image Text:A 6.22 kg particle with velocity v = (9.72 m/s)î – (8.99 m/s)j is at x = 2.96 m, y = 5.29 m. It is pulled by a 5.05 N force in the negative x direction. About the origin, what are (a) the particle's angular momentum, (b) the torque acting on the particle, and (c) the rate at which the angular momentum is changing? (a) Number i k Units (b) Number i k Units (c) Number i k Units
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