A 1.00 kg particle with velocity = (4.28 m/s )i-(7.79 m/s )jis atx-8.75 m, y-3.55 m. It is pulled by a 3.50 N force in the negative x direction. About the origin, what are (a) the particle's angular momentum, (b) the torque acting on the particle, and (c) the ate at which the angular momentum is changing?

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A 1.00 kg particle with velocity ✓ = (4.28 m/s )î – (7.79 m/s ) is at x = 8.75 m, y = 3.55 m. It is pulled by a 3.50 N force in the negative x direction. About the origin, what are (a) the particle's angular momentum, (b) the torque acting on the particle, and (c) the
rate at which the angular momentum is changing?
(a) Number
i
(b) Number i
(c) Number
i
k Units
k Units
k Units
Transcribed Image Text:- A 1.00 kg particle with velocity ✓ = (4.28 m/s )î – (7.79 m/s ) is at x = 8.75 m, y = 3.55 m. It is pulled by a 3.50 N force in the negative x direction. About the origin, what are (a) the particle's angular momentum, (b) the torque acting on the particle, and (c) the rate at which the angular momentum is changing? (a) Number i (b) Number i (c) Number i k Units k Units k Units
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