**Problem Statement:**A 10.0 kg toy car moves along an x-axis with a velocity given by \( \vec{v} = -7.89t^3 \hat{\imath} \, \text{m/s} \), with \( t \) in seconds. For \( t > 0 \), calculate:- (a) the angular momentum \( \vec{L} \) of the car about the origin.- (b) the torque \( \vec{\tau} \) on the car about the origin.Calculations are also required for:- (c) \( \vec{L} \) about the point (5.92 m, 6.76 m, 0).- (d) \( \vec{\tau} \) about the point (5.92 m, 6.76 m, 0).- (e) \( \vec{L} \) about the point (5.92 m, -6.76 m, 0).- (f) \( \vec{\tau} \) about the point (5.92 m, -6.76 m, 0).**Calculation Template:**For each of the above calculations, fill in the appropriate values into the expressions below:- \((a)\) \( \left( \_\_\_ \right) \hat{\jmath} + \left( \_\_\_ \right) \hat{k} \)- \((b)\) \( \left( \_\_\_ \right) \hat{\imath} + \left( \_\_\_ \right) \hat{k} \)- \((c)\) \( \left( \_\_\_ \right) \hat{\imath} + \left( \_\_\_ \right) \hat{k} \cdot t^3 \)- \((d)\) \( \left( \_\_\_ \right) \hat{\imath} + \left( \_\_\_ \right) \hat{k} \cdot t^2 \)- \((e)\) \( \left( \_\_\_ \right) \hat{\imath} + \left( \_\_\_ \right) \hat{k} \cdot t^3 \)- \((f)\) \( \left( \_\_\_ \right) \hat

“Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for you. To get remaining sub-part solved please repost the complete question and mention the sub-parts to be solved.”Given mass of a toy is m=10kg and its velocity is Therefore its position at any instant t is a) therefore angular momentum of the toy with respect to origin is b) torque on the toy with respect to origin is thereforec) Now position of point say P (5.92,6.76,0) is Therefore position of toy with respect to point P is Therefore angular momentum of the toy with respect to point P is This is the answer.

Answered: A 10.0 kg toy car moves along an x axis…