A particle is located at the position vector r = (6.00î + 7.0oj) m and a force exerted on it is given by F = (4.00î + 3.00j) N. (a) What is the torque acting on the particle about the origin? N.m
A particle is located at the position vector r = (6.00î + 7.0oj) m and a force exerted on it is given by F = (4.00î + 3.00j) N. (a) What is the torque acting on the particle about the origin? N.m
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Problem Statement:**
A particle is located at the position vector \( \vec{r} = (6.00 \hat{\imath} + 7.00 \hat{\jmath}) \) m and a force exerted on it is given by \( \vec{F} = (4.00 \hat{\imath} + 3.00 \hat{\jmath}) \) N.
(a) What is the torque acting on the particle about the origin?
\[ \tau = \text{______} \, \text{N} \cdot \text{m} \]
**Explanation:**
Here, we need to calculate the torque (\( \tau \)) acting on the particle about the origin. Torque is given by the cross-product of the position vector (\( \vec{r} \)) and the force vector (\( \vec{F} \)).
To find the torque \( \tau \):
\[ \tau = \vec{r} \times \vec{F} \]
\[ \vec{r} = (6.00 \hat{\imath} + 7.00 \hat{\jmath}) \, \text{m} \]
\[ \vec{F} = (4.00 \hat{\imath} + 3.00 \hat{\jmath}) \, \text{N} \]
The torque \( \vec{\tau} \) is computed as:
\[ \vec{\tau} = (6.00 \hat{\imath} + 7.00 \hat{\jmath}) \times (4.00 \hat{\imath} + 3.00 \hat{\jmath}) \]
Solve the cross product to find the magnitude and direction.
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This transcribed text can be used in educational resources to provide students practice in vector cross product and understanding torque.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F251d1f23-479f-46f1-ad40-8e7a3447a718%2F5030e37f-dc06-49a4-936d-6732265b62e8%2F3t1lu6p_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
A particle is located at the position vector \( \vec{r} = (6.00 \hat{\imath} + 7.00 \hat{\jmath}) \) m and a force exerted on it is given by \( \vec{F} = (4.00 \hat{\imath} + 3.00 \hat{\jmath}) \) N.
(a) What is the torque acting on the particle about the origin?
\[ \tau = \text{______} \, \text{N} \cdot \text{m} \]
**Explanation:**
Here, we need to calculate the torque (\( \tau \)) acting on the particle about the origin. Torque is given by the cross-product of the position vector (\( \vec{r} \)) and the force vector (\( \vec{F} \)).
To find the torque \( \tau \):
\[ \tau = \vec{r} \times \vec{F} \]
\[ \vec{r} = (6.00 \hat{\imath} + 7.00 \hat{\jmath}) \, \text{m} \]
\[ \vec{F} = (4.00 \hat{\imath} + 3.00 \hat{\jmath}) \, \text{N} \]
The torque \( \vec{\tau} \) is computed as:
\[ \vec{\tau} = (6.00 \hat{\imath} + 7.00 \hat{\jmath}) \times (4.00 \hat{\imath} + 3.00 \hat{\jmath}) \]
Solve the cross product to find the magnitude and direction.
---
This transcribed text can be used in educational resources to provide students practice in vector cross product and understanding torque.

Transcribed Image Text:**Instruction (f): Determine the Position Vector**
For this task, you are required to determine the position vector of a point located on the y-axis.
**Vector Representation:**
- The vector is represented as **\(\vec{r} = \_\_\_\_\_\_ \, \text{m}\)**.
- You need to specify the vector's value within the provided box to denote the position on the y-axis.
The position vector typically has the format \(\vec{r} = (x, y, z)\). Since the point is on the y-axis, x and z components would be zero, resulting in a vector of the form \((0, y, 0)\). Specify a value for \(y\) based on the context to complete the answer.
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