Answered: At time t-0, a 4.61 kg particle has… | bartleby

Related questions

Question

At time t-0, a 4.61 kg particle has position vector 7 (5.00 m )7-(6.00 m) relative to the origin. Its velocity is given by
3=(-1.35² m/s ) for t in seconds. About the origin with t-12.8 s, what are (a) the particle's angular momentum and (b) the
torque acting on the particle, both in unit-vector notation?
(a) Number
(b) Number
Units
Units

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

A system consists of three identical 5-kg particles A, B, and C. Their position vectors (in meter) and velocity vectors (in m/s) are r, = (0,0,3), v, = v j,r, = (2,2,3), v, = v,i, and r. = (1,4,0). v. = v k, respectively. Knowing that the angular momentum of the system about point O is H, = -1.5k kg m s, determine (a) the velocities of the particles, (b) the angular momentum of the system about its center of mass G.
Assume that (1) F = 10i +60j - 20k, acting at a point (8, 6, 4), and (2) two end points of a line L are A (2, 0, 4) and B (-7, 6, 2), respectively. Determine the moment of the force F about the line L. In the figure (a) is a force F and line L. (b) is the position vector r from A to the point of application of F.
In a long jump, an athlete sweeps one of her arm clockwise through 0.5 revolution and the other arm sweeps counterclockwise through 1.0 revolution in 0.7s. Treat each arm as a thin rod of mass 3.0. kg and length 0.5m rotating around one end. In the athlete’s reference frame, calculate the magnitude of the total angular momentum of the arms around the common rotation axis through the shoulders. (given I thin rod = MR^2)
A particle of mass 2.00 kg moves with position r(t) = x(t) i + y(t) j where x(t) = 10t2 and y(t) = -3t + 2, with x and y in meters and t in seconds. (a) Find the momentum of the particle at time t = 1.00 s.(b) Find the angular momentum about the origin at time t = 3.00 s.
The mass of an electron is 9.0 x 10-31 kg. It revolves around the nucleus of an atom in a circular orbit of radius 4.5 m, with a speed of 8.0 x 105 m/s. What is the angular momentum of an electron?
At time t, the position of a point particle of mass m = 3 kg is given by r = 4t^2i −(2t + 6t^2)jwhere r is in meters and t in seconds. (a) What is the angular momentum vector of the object at t = 5 s. (b) What is the torque vector acting on the object at t = 2
A particle of mass m is dropped from rest at t = 0 at the point (−d, 0, 0) and falls vertically in Earth's gravitational field −gĵ. (a) What is the expression for the angular momentum of the particle about the origin? (Express your answer in vector form. Use any variable or symbol stated above as necessary.) l = (b) Calculate the torque on the particle about the origin. (Express your answer in vector form. Use any variable or symbol stated above as necessary.) τ = (c) Is the torque equal to the time rate of change of the angular momentum? Yes No
A 40-gram point mass is traveling at a velocity of v = 2.6 m/sec parallel to the x-axis along the line y = 0.2 meters. What is its angular momentum with respect to the origin?
What is the angular momentum of a solid disk at t=2.5s if its mass is 0.25kg, its radius is 4m, and the torque applied to the disk is 1 N m?
I need the answer as soon as possible
At one instant, force: F = 5.14j N acts on a 0.297 kg object that has position vector 7 = (5.10î – 5.10k) m and velocity vector = (- 9.56i + 9.56k ) m/s .About the origin and in unit-vector notation, what are (a) the object's angular momentum and (b) the torque acting on the object? (a) Number k Units (b) Number k Units +
A 1.70-kg particle moves in the xy plane with a velocity of = (4.10 1-4.00 j) m/s. Determine the angular momentum of the particle about the origin when its position vector is F (1.50 +2.20 j) m. + j+ k) kg - m²/s

SEE MORE QUESTIONS