At a particular instant, a 1.0 kg particle's position is r = (6.0f - 5.0j + 3.0k) m, its velocity is v = (-1.0f + 5.0j + 1.0k) m/s, and the force on it is F = (13.0f + 17.0j) N. (Express your answers in vector form.) (a) What is the angular momentum (in kg · m2/s) of the particle about the origin? kg - m2/s (b) What is the torque (in N · m) on the particle about the origin? N. m (c) What is the time rate of change of the particle's angular momentum about the origin at this instant (in kg · m2/s2)? IP dt kg - m?/s2

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At a particular instant, a 1.0 kg particle's position is r = (6.0î – 5.0j + 3.0k) m, its velocity is v = (-1.0î + 5.0j + 1.0k) m/s, and the force on it is F = (13.0î + 17.0j) N. (Express your
answers in vector form.)
(a) What is the angular momentum (in kg · m2/s) of the particle about the origin?
kg · m2/s
(b) What is the torque (in N. m) on the particle about the origin?
N. m
(c) What is the time rate of change of the particle's angular momentum about the origin at this instant (in kg • m2/s?)?
di
kg - m?/s2
dt
Transcribed Image Text:At a particular instant, a 1.0 kg particle's position is r = (6.0î – 5.0j + 3.0k) m, its velocity is v = (-1.0î + 5.0j + 1.0k) m/s, and the force on it is F = (13.0î + 17.0j) N. (Express your answers in vector form.) (a) What is the angular momentum (in kg · m2/s) of the particle about the origin? kg · m2/s (b) What is the torque (in N. m) on the particle about the origin? N. m (c) What is the time rate of change of the particle's angular momentum about the origin at this instant (in kg • m2/s?)? di kg - m?/s2 dt
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